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Julli [10]
3 years ago
14

1. What kind of diagram shows how energy flows from one organism to another?

Chemistry
1 answer:
shusha [124]3 years ago
5 0
It would be D.the food chain
You might be interested in
A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60
Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0
2 years ago
g A chemist combines 59.9 mL of 0.282 M potassium bromide with 15.4 mL of 0.512 M silver nitrate. (a) How many grams of silver b
Rufina [12.5K]

Answer:

m_{AgBr}=1.48gAgBr

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

KBr(aq)+AgNO_3(aq)\rightarrow AgBr(s)+KNO_3(aq)

Thus, since the potassium bromide and silver nitrate are in a 1:1 mole ratio, the first step is to identify the limiting reactant, by considering the reacting volumes of reactants in order to compute the available moles of potassium bromide and the moles of potassium bromide consumed by the 15.4 mL of 0.512-M solution of silver nitrate:

n_{KBr}=0.0599L*0.282\frac{molKBr}{L} =0.0169molKBr\\\\n_{KBr}^{consumed}=0.0154L*0.512\frac{molAgNO_3}{L} *\frac{1molKBr}{1molAgNO_3}=0.00788molKBr

In such a way, since less moles are consumed than available, we infer that silver nitrate is the limiting reactant, for which the resulting grams of silver bromide (molar mass 187.8 g/mol) result:

m_{AgBr}=0.00788molAgNO_3*\frac{1molAgBr}{1molAgNO_3} *\frac{187.8gAgBr}{1molAgBr} \\\\m_{AgBr}=1.48gAgBr

Best regards.

6 0
3 years ago
1. Which of the following correctly represents a balance chemical equation? (a) NaCl + 2H2O → 2NaOH + 2Cl2 + H2 (b) 2NaCl+H2O →
butalik [34]

Answer:

thx sa points

Explanation:

8 0
2 years ago
Ascientist is measuring the pressure that is exerted by each of the following gases in the atmosphere: carbon dioxide, oxygen,
Rzqust [24]

Answer:

Partial pressure

Explanation:

the scientists is measuring different pressure, so it would be partial pressure. Hope that this helps you and have a great day :)

4 0
3 years ago
For the following formula, C4H9Cl, calculate the IHD and select all the types of unsaturation that might be present in the molec
Airida [17]

Answer:

The IHD = 0

There is no unsaturation in the compound C4H9Cl

Explanation:

IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:

For Molecule:

C_{c}H_{h}O_{o}N_{n}X_{x}

Here . C = carbon

H = Hydrogen

O = Oxygen

N = Nitrogen

X = Halogen

The IHD is calculated as :

\frac{2c-h-x+n+2}{2}...............(1)

For example :

C4H8O2

Here c = 4 , h = 8 , o = 2 .

n = x=0

Put the value in equation (1) and find IHD

\frac{2(4)-8-0+0+2}{2}

\frac{8-8+2}{2}

\frac{2}{2}

IHD = 1

For C4H9Cl

c = 4 , h = 9 and  x = 1

IHD for this molecule can be calculated as :

\frac{2c-h-x+n+2}{2}

\frac{2(4)-9-1+2}{2}

\frac{8-9-1+2}{2}

= 0

This means there is no unsaturation in the molecule.

Each bond is sigma bond and properly saturated.

5 0
3 years ago
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