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3 years ago

NaOH is a strong base. What two ions do you expect to find in a solution of NaOH?

Chemistry

1 answer:

Marrrta [24]3 years ago

7 0

According to Arrhenius concept a base is one which can donate hydroxide ion in its aqueous solution.

Here NaOH is a base as it can donate OH-.

As NaOH is a strong base it will have very high dissociation constant.

Due to high dissociation constant if will almost completely dissociate into sodium ions and hydroxide ions.

$NaOH --> Na^{+}(aq) + OH^{-}(aq)$

Thus in a solution of NaOH we will expect the following two ions

Na^{+} + OH^{-}[/tex]

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

3 years ago

How would the concentration of silver ions compare in a 1.0 x 10-16 L saturated solution to a 1.5 x 10-16 L saturated solution?

VMariaS [17]

The second one is more concentrated as they both times with the same thing but the second one (1.5) is bigger

3 0

3 years ago

How many moles are in 8.32 x 1024 molecules of CO2.

Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.32 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 13.820598...$

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

6 0

3 years ago

A group or family represents the *blank* on the periodic table

alekssr [168]

The answer is vertical column

8 0

3 years ago

An experiment reacts 20.4 g of zinc metal with a solution containing an excess of iron (III) sulfate. After the reaction, 10.8 g

quester [9]

Answer:

The answer to your question is 92.7%

Explanation:

Balanced Chemical reaction

3 Zn + Fe₂(SO₄)₃ ⇒ 2Fe + 3ZnSO₄

Molecular weight

Zinc = 65.4 x 3 = 196.2g

Iron (III) = 56 x 2 = 112 g

Proportions

196.2 g of Zinc ------------------ 112 g of Iron

20.4 g of Zinc ----------------- x

x = (20.4 x 112) / 196.2

x = 2284.8/196.2

x = 11.65 g of Iron

% yield = $\frac{10.8}{11.65} x 100$

% yield = 0.927 x 100

% yield = 92.7

5 0

3 years ago

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