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yanalaym [24]
3 years ago
13

In Niels Bohr’s model of the atom, how are electrons configured?

Physics
2 answers:
AnnyKZ [126]3 years ago
8 0

The statement "like planets orbiting the sun" best explains the Bohr's model. Niels Bohr postulated that electron revolve around the nucleus in specific orbitals which are quantized. These orbits are represented by the letters K.L.M,N. The maximum number of electrons in each orbit is determined by 2n^2, where n is the number of the orbit. When an electron absorbs energy it moves to a higher orbit, and it moves to a lower orbit when it emits energy. This movement produces discrete spectra which explains the reason for quantized energy levels.

olga nikolaevna [1]3 years ago
8 0

Answer:

like planets orbiting the sun

Explanation:

The Niels Bohr´s Model of the atom was arranged in a perfect center where the nucleus of the atom was located and then the electrons that surrounded the nucleus were orbiting the nucleus, it was thought to be always orbiting in perfect rounded shape orbits, like the planets around the sun, so that is why from the options the best suited would be planets orbiting the sun.

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In a belly-flop diving contest, the winner is the diver who makes the biggest splash upon hitting the water. the size
ad-work [718]

The second diver have to leap to make a competitive splash by 4.08 m high.

<h3>What is potential energy?</h3>

The energy by virtue of its position is called the potential energy.

PE = mgh

where, g = 9.81 m/s²

Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.

The potential energy of the first diver must be equal to the second diver.

P.E₁ = P.E₂

m₁gh₁ = m₂gh₂

Substitute the vales, we have

136 x 3  = 100 x h₂

h₂ = ₂4.08 m

Thus, the second diver need to leap by 4.08 m high.

Learn more about potential energy.

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7 0
2 years ago
A horse is running at 12m/s accelerated to 38m/s in 10 seconds. What is the horses acceleration.
ahrayia [7]

Answer:

A horse is running at 12m/s accelerated to 38m/s in 10 seconds. What is the horses acceleration.

2.6m/s^2

3 0
3 years ago
Tech A says parallel circuits are like links in a chain. Tech B says total current in a parallel circuit equals the sum of the c
rosijanka [135]

Answer: Only Tech B is correct.

Explanation:

First, tech A is wrong.

The circuits that can be compared with links in a chain are the series circuit, and it can be related to the links in a chain because if one of the elements breaks, the current can not flow furthermore (because the elements in the circuit are connected in series) while in a parallel circuit if one of the branches breaks, the current still can flow by other branches.

Also in a parallel circuit, the sum of the currents of each path is equal to the current that comes from the source, so Tech B is correct, the total current is equal to the sum of the currents flowing in each branch of the circuit.

4 0
3 years ago
An inductor is connected to a 26.5 Hz power supply that produces a 41.2 V rms voltage. What minimum inductance is needed to keep
alexira [117]

Answer:

The minimum inductance needed is 2.78 H

Explanation:

Given;

frequency of the AC, f = 26.5 Hz

the root mean square voltage in the circuit, V_{rms} = 41.2 V

the maximum current in the circuit, I₀ = 126 mA

The root mean square current is given by;

I_{rms} = \frac{I_o}{\sqrt{2} } \\\\I_{rms}  = \frac{126*10^{-3}}{\sqrt{2} }\\\\I_{rms}  =0.0891 \ A

The inductive reactance is given by;

X_l = \frac{V_{rms}}{I_{rms}} \\\\X_l= \frac{41.2}{0.0891}\\\\X_l = 462.4 \ ohms

The minimum inductance needed is given by;

X_l = \omega L\\\\X_l = 2\pi  fL\\\\L = \frac{X_l}{2\pi f}\\\\L = \frac{462.4}{2\pi *26.5}\\\\L = 2.78 \ H

Therefore, the minimum inductance needed is 2.78 H

7 0
3 years ago
During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0
oksian1 [2.3K]

Answer:

v = 384km/min

Explanation:

In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.

You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:

d=\frac{1,280,000,000km}{37,000}=34,594.59km

You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:

v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}

hence, the speed of the Hubble is approximately 384km/min

5 0
3 years ago
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