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3 years ago

Scientists use what properties to help them identify and classify matter

1 answer:

Volgvan3 years ago

5 0

Scientists use the physical and chemical properties to help them identify and classify matter. These physical and chemical properties are in a macro-perspective, in which these matter contains compounds, elements and atoms. Hence, matter can be classified in various ways, <span><span>
1. </span>Atomic number either atomic mass each element has</span>
<span><span>2. </span>By substance of that matter either pure substance or mixed substance</span> <span>
3. If they cannot reduce a certain substance into a much smaller quantified atomic structure then they they’ll use (2) to identify and classify it.</span>

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Define the following: Bronsted-Lowry acid - Lewis acid- Strong acid - (5 points) Problem 6: Consider the following acid base rea

Allushta [10]

Answer: Yes, $HCl$ is a strong acid.

acid = $HCl$ , conjugate base = $Cl^-$ , base = $H_2O$ , conjugate acid = $H_3O^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

Yes $HCl$ is a strong acid as it completely dissociates in water to give $H^+$ ions.

$HCl\rightarrow H^++Cl^-$

For the given chemical equation:

$HCl+H_2O\rightarrow H_3O^-+Cl^-$

Here, $HCl$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $Cl^-$ which is a conjugate base.

And, $H_2O$ is gaining a proton, thus it is considered as a base and after gaining a proton, it forms $H_3O^+$ which is a conjugate acid.

Thus acid = $HCl$

conjugate base = $Cl^-$

base = $H_2O$

conjugate acid = $H_3O^+$ .

8 0

3 years ago

Which best describes the asteroid belt

harina [27]

i think that the answer is d. millions of small rocky objects

5 0

3 years ago

Read 2 more answers

What is the mass of an object that has a density of 0.500 g/cm3 and a volume of 5.00 mL?

attashe74 [19]

Answer:

<h2>The answer is 2.5 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.5 g/cm³

1 mL = 1 cm³

5 mL = 5 cm³

volume = 5 cm³

The mass is

mass = 0.5 × 5

We have the final answer as

Hope this helps you

4 0

3 years ago

the more particles a substance has at a given temperature the more thermal energy it has true or false

Flauer [41]

Answer:

$\huge\boxed{\sf True}$

Explanation:

Temperature and thermal energy are in a direct proportion which means that if temperature of a substance increases, its thermal energy also increases and vice versa.

$\rule[225]{225}{2}$

Hope this helped!

4 0

3 years ago

216 J of energy is required to raise the temperature of a piece of aluminum from 15.0º C to to 35º C.

ddd [48]

Answer: 12g

Explanation:

The amount of energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 216 joules

Mass of aluminium = ? (let unknown value be Z)

C = 0.90 JºC-1g-1

Φ = (Final temperature - Initial temperature)

= 35°C - 15°C = 20°C

Then, Q = MCΦ

216 J = Z x 0.90 JºC-1g-1 x 20°C

216 J = Z x 18 J°g-1

Z = (216J/18 J°g-1)

Z = 12g

Thus, the mass of the aluminium is 12grams

8 0

3 years ago