Answer:
The temperature change is 12.5 °C
Explanation:
Step 1: Data given
Energy added to the water = 20950 joules of heat
Mass of water = 400 grams
The specific heat of water = 4.184 J/g°C
Step 2: Calculate the change in temperature
q = m*c*ΔT
⇒ with q = the energy (heat) added to the container = 20950 J
⇒ with m = the mass of water = 400 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = the change of temperature = TO BE DETERMINED
20950 J = 400 * 4.184 * ΔT
ΔT = 20950 J / (400*4.184)
ΔT = 12.5 °C
The temperature change is 12.5 °C
