A solid and a liquid are shaken together in a test tube to produce a uniform liquid that does not separate into layers.

In an experiment, 2.54 grams of copper completely reacts with sulfur, producing 3.18 grams of copper(I) sulfide.

kozerog [31]

Answer:

0.64 g of S

Solution:

The balance chemical equation is as follow,

2 Cu + S ----> Cu₂S

According to equation,

127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S

So,

2.54 g Cu will produce = X g of Cu₂S

Solving for X,

X = (2.54 g * 159 g) / 127 g

X = 3.18 g of Cu₂S

Now, it is confirmed that the reaction is 100% ideal. Therefore,

As,

127 g (2 mole) Cu required = 32 g (1 mole) of S

So,

2.54 g Cu will require = X g of S

Solving for X,

X = (2.54 g * 32 g) / 127 g

X = 0.64 g of S

5 0

3 years ago

Read 2 more answers

Homogeneous mixture that does not settle out upon standing reflect light is an element. solid. hydrated.

andrey2020 [161]

Homogeneous mixture that does not settle out upon standing but which will reflect light is called COLLOIDS.
There are three types of homogeneous mixtures, these are: solutions, colloids and suspension. Colloids are usually distinguished by Tyndall effects. Light passing through a colloidal dispersion will be reflected.<span />

5 0

3 years ago

How many grams of nan3 are required to produce 19.0 ft3 of nitrogen gas, about the size of an automotive air bag, if the gas has

Papessa [141]

The balanced chemical reaction is given as:

$2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)$

Now, convert $19.0 ft^{3}$ into litres.

$1 ft^{3} = 28.3168$

So, $19.0 ft^{3} = 19\times 28.3168 = 538.0192 L$

Density is equal to the ratio of mass to the volume.

$D=\frac{M}{V}$

where, M = mass and V= volume $(538.0192 L)$

Substitute the value of density and volume in formula to get the value of mass.

$1.25 g/L=\frac{M}{538.0192 L}$

$1.25 g/L\times 538.0192 L= M$

$Mass = 672.524 g$

Now, number of moles of $N_{2}$ gas= $\frac{672.524 g}{28.02 g/mol}$

= $24.00 moles$

According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.

Now, in 24.00 moles of nitrogen gas produced from= $\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles$ of nitrogen gas, moles of sodium azide.

number of moles of sodium azide = $16 moles$

Mass of sodium azide in g = $number of moles\times molar mass of sodium azide$ .

= $16 moles\times 65.00 g/mol$

= $1040 g$

Thus, mass of sodium azide which is required to produce $19.0 ft^{3}$ of nitrogen gas = $1040 g$

3 0

2 years ago

171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in o

Fantom [35]

The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?

a. 16mm Hg

b. 24mm Hg

c. 20mm Hg

d. 12mm Hg

Answer: The vapor pressure (VP) of this solution at $25^{o}C$ is closest to the value 24 mm Hg.