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Ilia_Sergeevich [38]
4 years ago
15

Which of the following best characterizes the global role of photosynthesis in relation to global warming?

Physics
1 answer:
Nostrana [21]4 years ago
4 0

Answer:

circulation i hope it helpsome

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A major difference between radio waves, visible light, and gamma rays is the ____ of the photons, which results in the different
olga2289 [7]
The sentence can be completed as follows:
"<span>A major difference between radio waves, visible light, and gamma rays is the energy of the photons, which results in the different photon frequencies and wavelengths."

In fact, gamma rays have greater energy than visible light and visible light has greater energy than radio waves. The energy E of a photon is related to its frequency, f, by
</span>E=hf
<span>where h is the Planck constant. We see from this formula that the higher the frequency, the greater the energy. Instead, the wavelength is inversely proportional to the frequency:
</span>\lambda= \frac{c}{f}
<span>where c is the speed of light. Since the frequency is directly proportional to the energy, this means that the wavelength is inversely proportional to the energy.</span>
8 0
3 years ago
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If the density of a substance is 5g/cm3 and the volume is 10cm3,<br> determine the mass.
vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

(5g/cm³)*(10cm³) = 50g

6 0
3 years ago
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Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The th
VikaD [51]

Answer:

what is this a riddle lol it breaks when he either jumps or lands

Explanation:

3 0
3 years ago
4.2 mol of monatomic gas A interacts with 3.2 mol of monatomic gas B. Gas A initially has 9500 J of thermal energy, but in the p
Komok [63]

Answer:

14657.32 J

Explanation:

Given Parameters ;

Number of moles mono atomic gas A ,   n 1  =  4 .2 mol

Number of moles mono atomic gas B ,   n 2  =  3.2mol

Initial energy of gas A ,   K A  =  9500  J

Thermal energy given by gas A to gas B ,   Δ K  =  600 J

Gas constant   R  = 8.314  J / molK

Let  K B  be the initial energy of gas B.

Let T be the equilibrium temperature of the gas after mixing.

Then we can write the energy of gas A after mixing as

(3/2)n1RT = KA - ΔK

⟹ (3/2) x 4.2 x 8.314 x T = 9500 - 600

T = (8900 x 3 )/(2x4.2x8.314) = 382.32 K

Energy of the gas B after mixing can be written as

(3/2)n2RT = KB + ΔK

⟹ (3/2) x 3.2 x 8.314 x 382.32 = KB + 600

⟹ KB = [(3/2) x 3.2 x 8.314 x 382.32] - 600

⟹ KB = 14657.32 J

6 0
4 years ago
Question 9 of 10
mixer [17]

Answer:

I believe the correct answer is B..<u>" 1 "</u>

Explanation:

hope it helps! ;)

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