Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m
1 answer:
Answer:
Therefore the escape velocity from Mar's gravity is m/s.
Explanation:
Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.
Escape velocity
G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²
M= mass of Mars = 6.42×10²³ kg
R = Radius of the Mars = 3.40×10³m
The escape velocity does not depend on the velocity of a object.
m/s
Therefore the escape velocity from Mar's gravity is m/s.
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Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m
Answer:
If a vertical line extending down from an object's CG extends outside its area of support, the object will topple
Explanation:
We can understand better this situation using a diagram with the forces acting on it.
In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.
