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shusha [124]
3 years ago
13

A hockey puck with mass 0.3 kg is shot across an ice-covered pond. Before the hockey puck was hit, the puck was at rest. After t

he hit, the puck has a speed of 40 m/s. The puck comes to rest after going a distance of 30 m. Find the magnitude of the net friction force.

Physics
2 answers:
kirill [66]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

JulsSmile [24]3 years ago
3 0

Answer:

The net friction force is 8.01 N

Explanation:

Net friction force = mass of hockey puck × acceleration

From the equations of motion

v^2 = u^2 + 2as

v = 40 m/s

u = 0 m/s (puck was initially at rest)

s = 30 m

40^2 = 0^2 + 2×a×30

60a = 1600

a = 1600/60 = 26.7 m/s^2

The acceleration of the puck is 26.7 m/s^2

Net friction force = 0.3 × 26.7 = 8.01 N

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Answer:

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Explanation:

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now the mass of the first car is two and half times and its kinetic energy is half that of other car

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now speed of both cars is increased by value of 9 m/s

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