Question

The wavelength of a sound wave in this room is 1.13 m and the frequency is 301 Hz.

Answer 1

Answer:

a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles

Explanation:

a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.

v = fλ = 301 Hz × 1.13 m = 340.13 m/s

b. If we double the frequency then f = 2 × 301 Hz = 602 Hz

v = fλ = 602 Hz × 1.13 m = 680.26 m/s

c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.

Since v = fλ,

λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.

Since our initial wavelength λ₀ = 1.13 m,

λ/λ₀ = 2.26 m/1.13 m = 2.

So, λ = 2λ₀ our wavelength doubles