All categories

3 years ago

Find the mass if the force is 18 N and the acceleration is 2 m/s2.

Physics

1 answer:

Flura [38]3 years ago

4 0

Answer:

<h3>The answer is 9 kg</h3>

Explanation:

To find the mass given the force and acceleration we use the formula

$m = \frac{f}{a} \\$

where

f is the force

a is the acceleration

We have

f = 18 N

a = 2 m/s²

We have

$m = \frac{18}{2} \\$

We have the final answer as

Hope this helps you

You might be interested in

How long does it take Larry to run 200 meters running at a speed of 21 m/s

andreev551 [17]

Answer:

9.52 seconds

Explanation:

t = d/v

t = 200 / 21

t = 9.52s (to 3 s.f.)

6 0

2 years ago

Read 2 more answers

In the early universe and in stars, deuterium nuclei are produced from the combination of one proton and one neutron, with the r

poizon [28]

Answer:

$Q = q_e = 1.6 \times 10^{-19} C$

Explanation:

As we know that charge is always conserved

so here we have

initial total charge = final total charge

also we know that gamma rays are chargeless and massless particles

so we have

charge on deuterium is given as

Q = charge on proton + charge on neutron - charge on gamma

so we have

$Q = 1.6 \times 10^{-19}$

$Q = q_e = 1.6 \times 10^{-19} C$

6 0

3 years ago

Why is using two thin blankets in bed usually warmer than one thick one?

Korolek [52]

I think it is because a big thick blanket has more room in it. if you have two thin blankets there isn't a whole lot there so it keeps the warmth in. <span />

4 0

4 years ago

Read 2 more answers

A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel

larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\$ (1)

R1 = 13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

$I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}$ (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

$R_{eq}=\frac{23V}{4A}=5.75\Omega$

Now, you can calculate the unknown resistor R2 by using the equation (1):

$\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega$

hence, the resistance of the unknown resistor is 10.31Ω

8 0

3 years ago

Read 2 more answers

Can somebody answer these I'm suspended and I have to catch up on my work and I dont have any notes.

ANTONII [103]

I can barley see turn it so I can see

8 0

3 years ago

Read 2 more answers