Two cylinders with the same mass density rC = 713 kg / m3 are floating in a container of water (with mass density rW = 1025 kg /
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Answer:
68 m
Explanation:
Given that the horizontal velocity of the birdman = 17 m/s and
the height, h= 78 m.
The gravitational force is acting in the downward direction, so it will not change the horizontal speed.
The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.
Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, m/s.
In the vertical direction, u = 0,
The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e
s= 78 m
Let t be the time taken to cover a distance of 78 m.
Now, applying the equation of motion in the vertical direction,
where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.
Here, , so
seconds.
Hence, the time taken to reach the ground is 4 seconds.
As the horizontal speed, m/s, is constant throughout the journey, so
the horizontal distance covered by turd
m.
So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly above the start of the field.
Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.
Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity = 60 mph = 26.8224 m/s
Final velocity = 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk = m(
² -
² )
we substitute
Δk = ×1814.37( (26.8224)² - (13.4112)² )
Δk = × 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Answer:
23. 4375 m
Explanation:
There are two parts of the rocket's motion
1 ) accelerating (assume it goes upto h1 height )
using motion equations upwards
Lets find the velocity after 2.5 seconds (V1)
V = U +at
V1 = 0 +5*2.5 = 12.5 m/s
2) motion under gravity (assume it goes upto h2 height )
now there no acceleration from the rocket. it is now subjected to the gravity
using motion equations upwards (assuming g= 10m/s² downwards)
V²= U² +2as
0 = 12.5²+2*(-10)*h2
h2 = 7.8125 m
maximum height = h1 + h2
= 15.625 + 7.8125
= 23. 4375 m