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atroni [7]
3 years ago
10

A car with an initial speed of 6.64 m/s accelerates at a uniform rate of 0.85 m/s^2 for 3.7s. The final speed of the car is 9.8

m/s. What is the cars displacement after that time? answer in km.
Physics
2 answers:
Shtirlitz [24]3 years ago
5 0

Answer:

So the car displacement after 3.7 sec is 0.030 km

Explanation:

We have given initial velocity u = 6.64 m/sec

Acceleration a=0.85m/sec^2

Time t = 3.7 sec

Final velocity v = 9.8 m/sec

We have to find the displacement after that time

From second equation of motion we know that s=ut+\frac{1}{2}at^2, here s is displacement, u is initial velocity, t is time , and a is acceleration

So displacement s=ut+\frac{1}{2}at^2=6.64\times 3.7+\frac{1}{2}\times 0.85\times 3.7^2=30.386m

We know that 1 km = 1000 m

So 30.386 m = 0.030 km

Lilit [14]3 years ago
4 0

Answer:

The  displacement of car after that time is 30.56 m.

Explanation:

Given that,

Initial velocity = 6.64 m/s

Acceleration = 0.85 m/s²

Time = 3.7 s

Final velocity = 9.8 m/s

We need to calculate the displacement

Using equation of motion

v^2=u^2+2as

s=\dfrac{v^2-u^2}{2a}

Put the value into the formula

s=\dfrac{9.8^2-6.64^2}{2\times0.85}

s =30.56\ m

Hence, The  displacement of car after that time is 30.56 m.

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A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an
Dominik [7]

Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

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put here value and find k

k = \frac{5*9.8}{.01}

k = 490 N/m

and ω is

ω = \sqrt{\frac{k}{m} }

ω = \sqrt{\frac{490}{5} }

ω = 9.9

so here position w.r.t  time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

8 0
3 years ago
Convert 10 kilowatt to watt​
Nataly [62]

Answer:

0.01 kilowatts cubed

Explanation:

just ask alexa lol

3 0
3 years ago
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Two toroidal solenoids are wound around the same form so that the magnetic field of one passes through the turns of the other. S
dedylja [7]

The concept that we need here to give a proper solution is mutual inductance.

The mutual inductance  is given by the expression

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Part A) Then we have in our values that,

I=6.6A

\Phi= 3.50*10^{-2}Wb

N=450

Replacing in the equation,

M = \frac{450*350*10^{-2}}{6.60}

M = 2.39H

Part B) Here is required the Flux, then using the same expression we have that

\Phi = \frac{IM'}{N}

We conserve the same value for the Inductance but now we have a current of 2.6, then

\Phi = \frac{2.6*2.39}{690}

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8 0
3 years ago
A 125 N box is being raised from the ground floor and accelerating due to a 175 N force. Identify all the forces and find the Ne
Finger [1]

Answer:

<em>Fn = 50 N</em>

Explanation:

<u>Net Force</u>

The net force is the sum of all the forces acting on an object.

When all the forces act in a single line, the direction of the forces is given by their signs. Positive signs are assumed to be up and left on both axes.

The box being raised by a force has a weight of W=-125 N. The negative sign indicates the weight points down. The accelerating force goes up and its value is F=175 N. The positive sign indicates this force pushes the box up.

The forces acting on the box are:

The weight W=-125 N

The accelerating force F=175 N

The net force is

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7 0
2 years ago
Light from a laser with wavelength 400 nm passed through two small openings and produces an interference pattern on a screen 1 m
alexira [117]

To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

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Our values are given as,

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\text{Distance of Screen} = D = 1m

Using the previous expression we have,

d \times \theta = \frac{\lambda}{2}

d \times (0.1) = \frac{4*10^{-7}}{2}

d = 2*10^{-6} m

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Therefore the distance between the two openings is 2\mu m

8 0
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