Answer:
T_ww = 43,23°C
Explanation:
To solve this question, we use energy balance and we state that the energy that enters the systems equals the energy that leaves the system plus losses. Mathematically, we will have that:
E_in=E_out+E_loss
The energy associated to a current of fluid can be defined as:
E=m*C_p*T_f
So, applying the energy balance to the system described:
m_CW*C_p*T_CW+m_HW*C_p*T_HW=m_WW*C_p*T_WW+E_loss
Replacing the values given on the statement, we have:
1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C=1.8 kg/s*4,18 kJ/(kg°C)*T_WW+30 kJ/s
Solving for the temperature Tww, we have:
(1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C-30 kJ/s)/(1.8 kg/s*4,18 kJ/(kg°C))=T_WW
T_WW=43,23 °C
Have a nice day! :D
Answer:

Explanation:
The charge transferred charge Q= −10nC = -10*10-9 C
Charge of a electron : 
Number of electrons transferred: 
42.5g
Explanation:
Given parameters:
Mass of N₂= 35g
Unknown:
Mass of NH₃ = ?
Solution:
Equation of the reaction:
N₂ + 3H₂ → 2NH₃
To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.
Number of moles of N₂ = 
molar mass of N₂ = 28g/mol
Number of moles =
= 1.25moles
From the equation of the reaction:
1 mole of N₂ produced 2 moles of NH₃
1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃
Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃
= 2.5 x (14 + 3)
= 42.5g
Learn more:
number of moles brainly.com/question/1841136
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Answer:
150 I would believe that it is the correct answer