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Nastasia [14]
3 years ago
7

A medicine is given 73 grains ap/lbs. of patient per dose. The patient weighs 65.7 kilograms. how many drams ap should the apoth

ecary tell the patient to take per dose?
Chemistry
1 answer:
erastova [34]3 years ago
3 0

10,573.4

Explanation:

Given parameters:

Dosage per patient = 73ap/lbs

Weight of patient = 65.7kg

Unknown:

Amount of grams/ap to be given to the patient;

 

Solution:

Since our final answer should be expressed in grams, let us convert all units into grams.

   1000g = 1kg

 Converting 65.7kg to g = 65.7 x 1000 = 65700g

73ap/lbs;

      1lb = 453.6g

 73ap/lbs x \frac{1lb}{453.6g} = 0.161ap/g

Now,

 For a 65700g person, the number of grains app required;

      65700 x 0.161 = 10,573.4grains ap per dose

learn more:

Mass brainly.com/question/3764212

#learnwithBrainly

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Consider the balanced equation for the following reaction:
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Answer:

In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.

Explanation:

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Mass of Al = 78.0 grams

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Atomic mass Al = 26.99 g/mol

Step 2: The balanced equation

6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)

Step 3: calculate moles HCl

Moles HCl = mass HCl / molar mass HCl

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Step 4: Calculate moles Al

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Moles Al = 2.89 moles

Step 5: Calculate the limiting reactant

For 6 moles HCl we need 2 moles Al  to produce 3 moles H2 and 2 moles AlCl3

HCl is the limiting reactant. It will completely be consumed (1.89 moles). Aluminium is the reactant in excess. There will react 1.89 / 3 = 0.63 moles

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In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.

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A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu
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83.3 mL

Explanation:

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Unknown:

V_{f} = ?

Solution:

To solve this problem we must understand that the initial and final number of moles remains the same.

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Molarity x volume of initial solution = Molarity x volume of final solution

 Therefore:

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M is the molarity

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8 0
3 years ago
Read 2 more answers
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