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3 years ago

How is the oxidation state of a transition metal determined from the chemical

Chemistry

2 answers:

rosijanka [135]3 years ago

8 0

Answer:it's D

Explanation:

Just took a quiz

natima [27]3 years ago

5 0

Answer:

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

Explanation:

A. A superscript on the transition metal identifies its oxidation state

in the formula.

This is wrong! Superscript are usually not written in formula of compound and for those that have superscripts, it refers to the oxidation number of the compound as a whole.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

This is wrong! Subscripts shows how many atoms of the element is present.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

This is correct! Examples include; manganese (II) oxide, Potassium manganate (VII) etc

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

This is wrong! Because there are cases of other metals or cations being present in the compound aside the transition metal

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natta225 [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

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Explanation:

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8 0

3 years ago

When performing labratory experiments, which of the following items is ALWAYS necessary to use?

densk [106]

All of the the answers are are correct but a fume hood is more for if you are dealing with chemicals that can produce fumes the are deadly to people

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3 years ago

Identify the neutral element represented by this excited-state electron configuration, then write the ground-state electron conf

sineoko [7]

Answer:

1s² 2s² 2p³

Nitrogen

Explanation:

Excited state configuration: 1s² 2s² 2p² 3s¹

Unknown:

Ground state configuration = ?

Element symbol = ?

Solution:

Let us start by understanding what a ground state configuration entails:

A ground state configuration shows the lowest allowed energy levels of an atom. The excited state denotes when electrons have moved to higher energy levels away from their ground state.

The superscript in the configuration depicts the number of electrons in each of the sublevels.

We can use this number to identify the atom we are dealing with:

Total number of electrons = 2 + 2 + 2 + 1 = 7 electrons

The element with 7 electrons on the periodic table is Nitrogen.

Now, the ground state configuration:

In writing the electronic configuration of an atom, certain rules must be complied with.

Aufbau's principle states that the sublevels with lower energies are filled up before those with higher energies. The order of filling is:

1s 2s 2p 3s 3p 4s etc

To fill the s-orbital = 2 electrons

p-orbital = 6 electrons

The outermost shell electrons are usually the ones excited.

Now, the 3s¹ shell is an excited one taking 1 electron from the second energy level;

The ground state configuration is 1s² 2s² 2p³

5 0

3 years ago

Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un

maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

Mass of graphite (m): 566.0 mg

Initial temperature: 5.2 °C

Final temperature: 23.2 °C

Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0

3 years ago

2 H2 + 2 NO → N2 + 2 H2O the observed rate expression, under some conditions, is: rate = k[NO]2 Which of the following mechanism

guapka [62]

Explanation:

Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.

$Rate \propto [\text{concentration of reactant}]^{n}$

= k $[\text{concentration of reactant}]^{n}$

where, k = rate constant

n = order of reaction

For the given reaction, $2H_{2} + 2NO \rightarrow N_{2} + 2H_{2}O$

Hence, its rate will be as follows.

Rate = $k[H_{2}][NO]$

Also, it is known that slowest step in a chemical reaction is the rate determining step.

Hence, for the given rate law correct reaction is as follows.

Step 1 : $H_{2} + NO \rightarrow N + H_{2}O$ (slow)

Balancing this equation it becomes $H_{2} + 2NO \rightarrow N_{2}O + H_{2}O$ (slow)

Step 2: $N_{2}O + H_{2} \rightarrow N_{2} + H_{2}O$ (fast)

4 0

3 years ago