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3 years ago

How is the oxidation state of a transition metal determined from the chemical

Chemistry

2 answers:

rosijanka [135]3 years ago

8 0

Answer:it's D

Explanation:

Just took a quiz

natima [27]3 years ago

5 0

Answer:

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

Explanation:

A. A superscript on the transition metal identifies its oxidation state

in the formula.

This is wrong! Superscript are usually not written in formula of compound and for those that have superscripts, it refers to the oxidation number of the compound as a whole.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

This is wrong! Subscripts shows how many atoms of the element is present.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

This is correct! Examples include; manganese (II) oxide, Potassium manganate (VII) etc

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

This is wrong! Because there are cases of other metals or cations being present in the compound aside the transition metal

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When elements that form a mineral dissolve in hot water, they form a mixture called a(n) ______.?

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2 years ago

What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim

Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means $P_{2} =\frac{P_{1} }{10}$

Given the volume of the system increased by 5 times which means $V_{2} =5\times V_{1}$

Given final temperature $T_{2}=150K$

Let the initial temperature be $T_{1}$

We know that PV=nRT

As n and R are constant $\frac{PV}{T}=constant$

$\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}$

$T_{1} =2\times T_{2}$

T1=300K

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2 years ago

Chemistry Help (Naming Oxyacids Chart)

guapka [62]

Answer:

HClO₃ /chloric acid /suffix -ic/ ClO₃⁻ (chlorate)

HClO₂/ chlorous acid/ suffix -ous/ ClO₂⁻ (chlorite)

HNO₃ /nitric acid /suffix -ic/ NO₃⁻ (nitrate)

HNO₂/ nitrous acid/ suffix -ous/ NO₂⁻ (nitrite)

Explanation:

Chlorine has 4 positive oxidation numbers to form oxyacids: +1, +3, +5 and +7.

When it uses the oxidation number +5, it forms HClO₃, which is named chloric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion ClO₃⁻ (chlorate).

When it uses the oxidation number +3, it forms HClO₂, which is named chlorous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion ClO₂⁻ (chlorite).

Nitrogen has 2 positive oxidation numbers to form oxyacids: +3 and +5.

When it uses the oxidation number +5, it forms HNO₃, which is named nitric acid, with the suffix -ic. When it loses an H⁺, it forms the oxyanion NO₃⁻ (nitrate).

When it uses the oxidation number +3, it forms HNO₂, which is named nitrous acid, with the suffix -ous. When it loses an H⁺, it forms the oxyanion NO₂⁻ (nitrite).

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2 years ago

Which coefficient before potassium (K) balances this chemical equation?

miskamm [114]

Answer:

The coefficient before potassium (K) balances this chemical equation is 2.

Explanation:

_K +Cl₂ → 2KCl

K =1 ; Cl =2

K=1 × 2 = 2

Cl = 1 × 2 = 2

2 K +Cl₂ = 2 KCl

5 0

3 years ago

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