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Dmitry_Shevchenko [17]
2 years ago
11

The specific heat capacity of thallium is 0.128 J/gC. A sample of thallium weighing 32.9 g is heated from 49C to its melting poi

nt(303 C). Calculate the energy change involved.
Chemistry
1 answer:
jeka942 years ago
7 0

Answer:

Thallium absorbed 1069.645 J heat to reach to its melting point.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of thallium = 32.9 g

specific heat capacity of thallium = 0.128 j/g. °C

Initial temperature = 49 °C

Final temperature = 303 °C

Solution:

Change in temperature = T₂- T₁

ΔT = 303 °C - 49 °C = 254 °C

Formula:

Q = m.c. ΔT

Q = 32.9 g ×0.128 j/g. °C × 254 °C

Q = 1069.645 J

Thallium absorbed 1069.645 J heat to reach to its melting point.

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zepelin [54]

Answer:

A chemist searches for new knowledge about chemicals and use it to improve the way we live. He or she may develop products such as synthetic fibers, drugs and cosmetics. Chemists create processes, including all refining and petrochemical processing, that reduce energy use and pollution.

8 0
3 years ago
1 A 3.80 g sample of bronze was dissolved in sulphuric acid. The copper in alloy reacted with
s344n2d4d5 [400]

Answer:

yeyeye

Explanation:

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3 0
2 years ago
A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.
Rufina [12.5K]
From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1 
mm1 = 71/1.87²
         = 71/3.4969
         = 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon
6 0
3 years ago
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:
soldi70 [24.7K]

Answer:

2.01V ( To three significant digits)

Explanation:

First we show the standard reduction potentials of Cu2+(aq)/Cu(s) system and Al3+(aq)/Al(s) system. We can clearly see from the balanced redox reaction equation that aluminium is the anode and was the oxidized specie while copper is the cathode and was the reduced specie. This observation is necessary when substituting values of concentration into the Nernst equation.

The next thing to do is to obtain the standard cell potential as shown in the image attached and subsequently substitute values of concentration and standard cell potential into the Nernst equation as shown. This gives the cell potential under the given conditions.

5 0
2 years ago
how many grams of antifreeze would be required per 500 g of water to prevent the water from feezing at a temperature of -39° C​
andrezito [222]

Answer:

333.7g of antifreeze

Explanation:

Freezing point depression in a solvent (In this case, water) occurs by the addition of a solute. The law is:

ΔT = Kf × m × i

Where:

ΔT is change in temperature (0°C - -20°C = 20°C)

Kf is freezing point depression constant (1.86°C / m)

m is molality of solution (moles solute / 0.5 kg solvent -500g water-)

i is Van't Hoff factor (1, assuming antifreeze is ethylene glycol -C₂H₄(OH)₂)

Replacing:

20°C = 1.86°C / m  × moles solute / 0.5 kg solvent × 1

5.376 = moles solute

As molar mass of ethylene glycol is 62.07g/mol:

5.376 moles × (62.07g / 1mol) = <em>333.7g of antifreeze</em>.

4 0
3 years ago
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