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3 years ago

What is the molar mass of sodium carbonate (Na2CO3)?

Chemistry

2 answers:

professor190 [17]3 years ago

8 0

The molar madd of sodium carbonate is 105.9888g/mol

madreJ [45]3 years ago

4 0

Answer:

105.9888 g/mol

Explanation:

The molar mass of sodium carbonate is 105.9888 g/mol (grams per mole)

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lidiya [134]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

Chlorine reacts with sodium and with hydrogen.

Sonbull [250]

Answer:

Sodium Chloride has Ionic bond while Hydrogen Chloride has covalent bond.

Explanation:

Na has 11 electrons (2, 8, 1) and need to give away 1 electron to be stable

Cl has 17 electrons ( 2, 8, 7) and needs 1 electron to be stable.

Na transfers 1 electron to CL to form Ionic bond.

While

Hydrogen has 1 electron and shares with Chlorine to be stable.

Covalent bond involves sharing.

3 0

2 years ago

What is the volume (in cubic inches) of 3.6 lb of titanium? The density of titanium is 4.51 g/cm3

SashulF [63]

Answer: 362,07 cm3
To answer this question you need to convert the lb into gram first. One lb equal to 453.592g, so: 3.6lb x 453.592gram/lb= 1632.9312gram.
Now we have mass(1632.9312g), density (4.51g/cm3). Volume is mass divided by density. The equation would be:

Volume= mass/density
Volume = 1632.9312gram / (4.51g/cm3)= 362,07 cm3

6 0

2 years ago

Some chemical bonds are considered molecules while others are considered compounds.

taurus [48]

Molecule is the general term used to describe any atoms that are connected by chemical bonds. Every combination of atoms is a molecule. A compound is a molecule made of atoms from different elements. All compounds are molecules, but not all molecules are compounds.

One example of a molecule is $Cl_2$ (chlorine).

Examples of a compound is NaCl (sodium chloride) or $H_2O\\$ (water)

5 0

2 years ago

Give regents and mechanism

Kryger [21]

Answer:

Reagents: 1) $BH_3$ 2) $H_2_O2$ , $OH^-$

Mechanism: Hydroboration

Explanation:

In this case, we have a hydration of alkenes reaction. But, in this example, we have an anti-Markovnikov reaction. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: "hydroboration".

The first step of this reaction is the addition of borane ( $BH_3$ ) to the double bond. Then in the second step, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the third step, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond " $BH_2-O-OH$ ". In step number 4 we have the migration of the C-B bond to oxygen. Then in step number 5, we have the attack of $OH^-$ on the $O-BH_2$ to produce an alkoxide. Finally, the water molecule produce in step 2 will protonate the molecule to produce the alcohol.

See figure 1

I hope it helps!

4 0

3 years ago