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3 years ago

The liquid form of matter is usually more dense than its: solid form gas form both solid and gas forms

1 answer:

5 0

<span>The liquid form of matter is usually more dense than its gas form. This is because liquid molecules are closer together compared to gas molecules. An exception, however, is water. Water's solid form or ice is less dense than its liquid form because of the orientation of hydrogen bonds that lowers its density.</span>

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A substance that does not conduct electricity as a solid but does conduct electricity when melted is most likely classified as

sweet-ann [11.9K]

Ionic compunds are able to conduct electricity when molten/in solution, but not when they are solid

5 0

3 years ago

Read 2 more answers

Is it possible to add an atom with 12 protons and 13 electrons explain

Svetllana [295]

No, it is not possible. No.To gain a stable octet configuration, it would either lose 2e- (but question shows 13 e-) or else gain 6e- (which creates a great energy difference)

3 0

3 years ago

Use the bond energies to answer the question.

Schach [20]

Answer:

Explanation:

Hello!

This is a topic I just learned this year so I might not help the best as of explaining. But I will try my best.

To solve this problem, we must first figure the balanced equation.

H₂+O₂=H₂O₂

Now, we have to find the bond energy of the reactants and products. This is how.

Let's find the reactant first.

For the compound H₂, the Lewis dot structure says that it only consists of one singular bond. So the bond energy of H₂ would be 432.

For the compound O₂, the Lewis dot structure that is the best out of the resonance structures form a double bond. Let's use the bond energy 495 for this since there are double bonds and we need the corresponding double bond energy to make the bond energy accurate.

Let's add this amount together. 927

Now, we have to find the bond energy of the products.

H₂O₂ sounds complicated but it's fairly easy. When you write the Lewis dot structure for this specific compound, you will get something along the lines of this:

H-O-O-H (disregarding lone pairs)

In this compound, there are two bonds of H-O and one bond that is a O-O. This might take you a long time to see this, but just think of what atom is touching the atom next door. This might help distinguish the bonds there are between the compound.

Let's take the bond energy of H-O (467) and multiply this by two since we have two. Add that number to the bond energy of O-O (146). We should have the numbers 1080.

Since the problem is asking for the difference in total energy between the reactants and products, let's subtract the total bond energy of the products-reactants.

1080-927=153

Therefore, your final answer of the total bond energy is 153.

4 0

2 years ago

When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen,

vampirchik [111]

N2 + 3H2 --> 2NH3
When 100g of N2 , no of moles of N2= 100/(28)=3.57 mol
no. of moles of h2 = 6/(2)=3mol
Therefore h2 is limiting reagent.
no. of moles of ammonia= 3/3*2=2moles
mass of ammonia produced= 2 mol * (14+3)= 34g

4 0

3 years ago

Read 2 more answers

Please comment if you are sure about your answer . Thank you

ryzh [129]

2,3,7,10,13 i did this yesterday can u mark me brainliest

3 0

3 years ago