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Lostsunrise [7]
3 years ago
13

The liquid form of matter is usually more dense than its: solid form gas form both solid and gas forms

Chemistry
1 answer:
Julli [10]3 years ago
5 0
<span>The liquid form of matter is usually more dense than its gas form. This is because liquid molecules are closer together compared to gas molecules. An exception, however, is water. Water's solid form or ice is less dense than its liquid form because of the orientation of hydrogen bonds that lowers its density.</span>
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An emulsifying agent is typically characterized by having ____. a. one polar end c. two polar ends b. one nonpolar end d. one po
tangare [24]

Answer:

An emulsifying agent is typically characterized by having <u><em>d. one polar end and one nonpolar end.</em></u>

Explanation:

Emulsifiers are substances that have the ability to bind, for example, fats with those substances that have mostly water in their conformation. In other words, the emulsifier facilitates mixtures of two or more immiscible liquid substances.

This is because the molecules of an emulsifier are often lipophilic (attract oil) at one end and hydrophilic (attract water) at the other. In other words it consists of a polar (hydrophilic) head group and a non-polar (hydrophobic) tail.

<u><em>An emulsifying agent is typically characterized by having d. one polar end and one nonpolar end.</em></u>

4 0
3 years ago
A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol. What is its molecular formula?.
Sonbull [250]

A molecule has an empirical formula of ch, and its molar mass is known to be 26 g/mol and the  molecular formula is C₂H₂ ethyne

Molecular formula of compound is (CH)n and the given molar mass is 26g/mol

Molar mass of (CH)n, C=12=n(12+1)=13n

So 13n and n=2

=13×2=26 and given molar mass is also 26g/mol

So here two carbon and two hydrogen so molecular formula is C₂H₂ and name is ethyne

Know more about molecular formula

brainly.com/question/28496692

#SPJ4

7 0
1 year ago
On a day wilderness expedition you'll need to heat of water to the boiling point each day. The air temperature will average . Yo
AlladinOne [14]

Answer:

36

Your question is not complere. but maybe it is like:

5 day expedition.

you'll need to heat 4.0kg

Air Temperature: 25 °C

each canister has 75 g

The standar heat of formation of propane at 25°C is −103.85 / kJmol...

If the data is not exactly the same, you can follow the same steps.

Explanation:

Given:

Weight of water = 4.0 kg = 4000 g

Boiling point  = 100 °C (T2)

Initial T ° Water= 25 °C (T1)

Specific heat capacity water (Cs) = 4.184 J / g°C

Then  

Energy (q) = m x Cs x (T2-T1)

q = 4000 g x  4.184 J / g°C x (100-25) °C

q = 1255200 J per day

For 5 days the amount of energy will be 5xq = 6276000 J = 6276 kJ

Then we know that the standard heat of formation of propane at 25°C is −103.85kJ/mol. Also, Molecular Weight propane= 44,1 g / mol

 

Then we can know how much propane it's needed:

Mass= 6276 kJ÷103.85 kJ / mol = 60.43 mol

Mass of propane= 60.43 mol ×  44,1 g/mol = 2664.9 g  

So, if each canister has 75.g of propane:  

Number of canister=  2664.9 g ÷ 75.g = 35.53 = 36 canisters

4 0
2 years ago
Read 2 more answers
Addition of 6 m hcl to which substance will not result in gas evolution?
saul85 [17]

There is no gaseous product when NaNO3 reacts with 6M HCl.

We must note that gas evolution is one of the signs that a chemical reaction has taken place. Hence, we must consider the options and look out for an option in which reaction with HCl does not lead to a gaseous product. This is the option that does not lead to evolution of a gas.

Let us consider the reaction; NaNO3(s) + HCl(aq) ---> NaCl(s) + HNO3(aq), there is no gaseous product hence NaNO3 does not result in gas evolution upon addition of 6M HCl.

Missing parts;

Addition of 6 M HCl to which substance will NOT result in gas evolution?

(A) Al

(B) Zn

(C) K2CO3

(D) NaNO3

Learn more about evolution of gas: brainly.com/question/2186340

6 0
2 years ago
Name the following bases<br> -Ba(OH)2<br> - Ca(OH)2<br> -RbOH
Harman [31]

Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}

Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}

RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}

3 0
2 years ago
Read 2 more answers
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