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OLga [1]
3 years ago
8

The main goal of developing technology is to___?

Chemistry
2 answers:
sammy [17]3 years ago
8 0

I believe the correct answer is C, but I'm 100% on this.  Hope this helped though!

-TTL

shutvik [7]3 years ago
4 0

Answer:

C

Explanation:

I did it and it is c

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1s22s22p63s23p64s13d10 which element is this
Sholpan [36]

Answer:

Copper

Explanation:

5 0
3 years ago
I. Give the name for the following compounds:
alexandr402 [8]

Answer:

Explanation:

1) MgBr₂

Magnesium bromide

2) Ca₃(PO₄)₂

Calcium phosphate

3) NO₂

Nitrogen dioxide

4) Ni₂(CO₃)₃

Nickel(III) carbonate

5) (NH₄)₂CO₃

Ammonium carbonate

6) MnBr₂

Manganese bromide

7) Na[MnO₄]

Sodium permanganate

8) P₂O₅

Phosphorus pentoxide

9) CCl₄

Carbon tetrachloride

10) Fe(OH)₂

Iron(ii) hydroxide

8 0
3 years ago
Biphenyl and benzene are common side products in this gringard reaction. explain at which points in the purification procedure t
mafiozo [28]

In Grignard reaction, Biphenyl and benzene are common side products which are removed during trituration.

In organic chemistry, a reaction in which the Grignard reagents or organometallic substances are added to organic compounds such as aldehydes and ketones to form alcohol is known as Grignard reaction.

These Grignard reagents are magnesium halides of alkyl, vinyl or allyl, which react with a carbonyl group to form alcohols.

During this reaction, primary, secondary and tertiary alcohols are formed.

While Biphenyl and benzene are common side products.

These are removed during trituration process in which cold petroleum ether is added to dissolve the biphenyl and benzene side products

If you need to learn more about Biphenyl and benzene click here:

brainly.com/question/4336669

4 0
1 year ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
This
timama [110]

Answer:

4.2 Liters (2 sig-figs)

Explanation:

Apply Boyles Law ... P₁V₁ = P₂V₂

P₁ = 712 Torr      P₂ = 3560 Torr

V₁ = 21.0L           V₂ = ?

P₁V₁ = P₂V₂ => V₂ = P₁V₁/P₂ = (712Torr)(21.0L)/(3560Torr) = 4.2 Liters (2 sig-figs)

8 0
3 years ago
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