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3 years ago

motorcycle accelerates from rest to a final velocity of 27 m/s in 9 seconds. What is its acceleration?

Physics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

3 m/s squared

Explanation:

The formula you use is Vf= Vi + at. You rearrange it to a= Vf - Vi/t. The Vf is 27m/s. The Vi is 0m/s and the t is 9s. Cross out Vi since it’s zero and you’re left with a= 27m/s divided by 9s, which equals 3

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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen

bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

$f_{a} =(\frac{v+v_{c} }{v} )f_{s}$ (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

$f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s}$ (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

$1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s$

b) Substitute eq. 1 in eq. 2:

$f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz$

7 0

3 years ago

Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than

Ymorist [56]

Answer:

1. F = ma F = 0.2kg * 20m/s² = 4Kg * m/s² = 4N

2. F = ma F - 18Kg * 3m/s² = 54Kg * m/s² = 54N

3. F = ma F = 0.025Kg * 5m/s² = 0.125N

4. F = ma F = 50Kg * 4m/s² = 200N

5. F = ma F = 70Kg * 4m/s² = 280N

6. F = ma F = 9Kg * 9.8m/s² = 88.2N

Explanation:

Hope this helps ! ^^

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2 years ago

In the standing waves experiment, the string has a mass of 31.2 g and a length of 0.7 m. The string is connected to a mechanical

mestny [16]

Answer:

linear density of the string = 4.46 × 10⁻⁴ kg/m

Explanation:

given,

mass of the string = 31.2 g

length of string = 0.7 m

linear density of the string = $\dfrac{mass\ of\ string}{length}$

linear density of the string = $\dfrac{31.2\times 10^{-3}\ kg}{0.7\ m}$

linear density of the string = 44.57 × 10⁻³ kg/m

linear density of the string = 4.46 × 10⁻⁴ kg/m

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3 years ago

Which of the following is true of high clouds?

Wewaii [24]

I’m pretty sure it’s B

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2 years ago

Which of Newton’s laws explains why a satellite continually orbits the earth and does not fall into the ground?

Nuetrik [128]

Answer:

Newtons 1st law of inertia

Explanation:

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3 years ago

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