Answer:

Explanation:
<u>Horizontal Launch
</u>
It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:
- The horizontal speed is constant and equal to the initial speed

- The vertical speed is zero at launch time, but increases as the object starts to fall
- The height of the object gradually decreases until it hits the ground
- The horizontal distance where the object lands is called the range
We have the following formulas




Where
is the initial horizontal speed,
is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.
If we know the initial height of the object, we can compute the time it takes to hit the ground by using

Rearranging and solving for t



We then replace this value in

To get



The initial speed depends on the initial height y=32.5 m, the range x=107.6 m and g=9.8 m/s^2. Computing 

The launch velocity is

It acquires a positive electric charge.
Answer:
Answer = 480000 joule.
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34. The element would have 34 protons. Also 34 electrons.
Answer:
The bikers speed at the top of other hill is <u>25.82 m/s.</u>
Explanation:
Considering the biker is riding on a frictionless surface.
∴ There is no non-conservative or external force acting on the biker.
Hence we can conserve the energy of biker and bike as a system.
Let,
= 44m
= 10m
Since the biker starts from rest , his initial speed
= 0 m/s
Let final speed of the bike at the top of other hill be
.
∴ Initial Energy (at the top of 44m hill) = 
Final Energy (at the top of 10m hill) =
.
Conserving both the energies , we get
= 
∴ 
Substituting the values for g ,
,
, we get
= 25.82 m/s