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Illusion [34]
3 years ago
6

A car rolls along a surface with a coefficient of friction of .795 I f the car has a mass of 905 kg, what force is needed to acc

elerate the car from rest to 102.5 km/hr in 10 sec?
Physics
1 answer:
Mumz [18]3 years ago
4 0
102.5 km/hr = 28.5 m/s
a = (28.5 - 0) / 10
a = 2.85 m/s²

Resultant force = forward force - friction
ma = F - μmg
F = ma + μmg
F = 905(2.85 + 0.795 x 9.81)
F = 9637.3 N
F = 9600 N
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What is motion? give 3 examples
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Motion definition: the action or process of moving or being moved.

Examples:

1. moving a hand

2. riding a bicycle

3. running

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3 years ago
A 2.1 cm length of tungsten filament in a small lightbulb has a resistance of 0.067 ω. find its diameter. the resistivity of the
kkurt [141]
The resistance of an ohmic material is given by 
R= \frac{ \rho l}{a}
where l is the length and a is the cross sectional area.  For a circular wire, this area is that of a circle:
R=  \frac{\rho l}{ {d^2} } \frac{4}{\pi}=\frac{5.6\times10^-8 \times0.021m\times4}{\pi d^2}   = \frac{1.497\times 10^-9}{d^2}
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3 0
3 years ago
Wind and weather patterns are caused when warm air near the surface of the Earth rises to higher levels in the atmosphere. The a
fomenos
Convection is the answer
3 0
3 years ago
Read 2 more answers
A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2
BartSMP [9]

Answer:

s = -0.100 \  m

Explanation:

Generally from kinematics equations we have that

          s = ut + \frac{1}{2}gt^2

Here u is the initial velocity of the rock and the value is  0 m/s given that there was no information that it was in motion before the fall

substituting 1.43 s for t and -9.8m/s^2 for g we have that

         s = 0 *1.43 + \frac{1}{2}(-9.8)*(0.143)^2

=>     s = -0.100 \  m

The negative sign show that the displacement is in the direction of the negative y-axis

 

7 0
3 years ago
A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire that has a 3.83 ×
Tju [1.3M]

Answer:

Explanation:

power of a heating element = V² / R where V is voltage and R is resistance

putting in the values

5200 = 75² / R

R = 1.082 ohm

Formula for resistance

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

1.082 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 8.29 m

b )

power of a heating element = V² / R , R is new resistance

5200 = 120² / R

R = 2.77 ohm

R = ρ L / S , ρ is resistivity , L is length and S is cross sectional area

2.77 = 5 x 10⁻⁷ x L / (3.83 x 10⁻⁶)

L = 21.22 m

4 0
3 years ago
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