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Marta_Voda [28]
3 years ago
14

Difference between clinical and laboratory thermometer

Chemistry
2 answers:
Mkey [24]3 years ago
8 0
Laboratory thermometer is used for gas and liquid substances whereas clinical thermometer is only used for the human body.
Setler79 [48]3 years ago
7 0

Answer:

1)clinical thermometer has temperature range 35 to 42degree celcius where labouratery thermometer has -10 to 110 degree celcius.

2)clinical thermometer is used to measure body temperature whare labouratory thermometer is not used to measure body temperature

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Woodpeckers find insects to eat by pecking holes in trees with their beaks. One day, a woodpecker finds a particular tree that o
bixtya [17]

Answer:

1. Reflex Conditioning

Explanation:

Conditioning is an aspect of learning where a stimulus works effectively in producing a response from an organism. This response becomes regular given the type of reinforcement that is administered to the organism. The reinforcement is usually a reward that is given to the organism.

This is what is observed in the woodpecker.  The stimulus or reinforcement which proves effective in producing a continuous response  from the woodpecker is the abundant supply of the birds favorite bugs. This reinforcement makes it possible for the woodpecker to become conditioned towards returning to the tree.

4 0
3 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
How would you prepare 3.5 L of a 0.9M solution of KCl?
Fudgin [204]
Calculate the mass of the solute <span>in the solution :

Molar mass KCl = </span><span>74.55 g/mol

m = Molarity * molar mass * volume

m = 0.9 * 74.55 * 3.5

m = 234.8325 g 

</span><span>To prepare 0.9 M KCl solution, weigh 234.8325 g of salt in an analytical balance, dissolve in a beaker, shortly after transfer with the help of a funnel of transfer to a volumetric flask of 100 cm</span>³<span> and complete with water up to the mark, then cover the balloon and finally shake the solution to mix

hope this helps!</span>
8 0
3 years ago
How many grams of kclo3 can be dissolved in 100 grams of water at 30 degrees Celsius
kondaur [170]
<span>The solubility of KClO</span>₃ : ( 10.1 / 100 g water ) at 30ºC

10.1 g ------------ 100 g ( H₂O )
    ? g ------------- 100 g ( H₂O )

Mass of KClO₃ :

100 * 10.1 / 100

1010 / 100 = 10.1 g of KClO₃

hope this helps!
8 0
3 years ago
A very loud sound has a high _____.
DENIUS [597]

Answer:

Resting Point

Explanation:

4 0
2 years ago
Read 2 more answers
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