Answer:
18.8 g
Explanation:
The equation of the reaction is;
AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)
Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles
Number of moles of LiBr = 10.23 g/86.845 g/mol = 0.1 moles
Since the molar ratio is 1:1, LiBr is the limiting reactant
Molar mass of solid AgBr = 187.77 g/mol
Mass of precipitate formed = 0.1 moles * 187.77 g/mol
Mass of precipitate formed = 18.8 g
Hey there!
density = 2.67 g/cm³
mass = 1340 g
volume = ?
Therefore:
D = m / V
2.67 = 1340 / V
V = 1340 / 2.67
V = 501.87 cm³
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Answer:
Do you still need this answer? :)
Explanation:
Explanation:
Very little to no formation of silver sulfate, as the silver sulfate Ksp( solubility product) is very large compared to the yellow precipitate Ksp.
By adding sodium sulfate to the silver / yellow precipitate mix, this question asks us to find a potential result and justification for the outcome. This implies that we will have to select the right answer that has a valid result and an adequate explanation for it. A substance's Ksp, or solubility product, is defined as the product of the dissolved ion concentration of each substance elevated to the power of its stoichiometric coefficient.
