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Makovka662 [10]
3 years ago
5

A solution containing 0.050 g of an unknown nonelectrolyte in 2.50 g of cyclohexane (Kf = 20.4 oC/m & F.P. 6.6 oC) was found

to freeze at 5.0 oC. What is the molar mass of the unknown substance?
Chemistry
1 answer:
ANEK [815]3 years ago
7 0

Answer:

The molar mass of the unknown substance is 255g/mole

Explanation:

Freezing point depression is given by

ΔT = i · Kf · m

Where

m = molality of the solute

i = van't Hoff's factor = i for non electrolyte

Kf = 20.4 °C/m = cryoscopic constant

ΔT = Freezing point depression

Therefore ΔT = 6.6 - 5 = 1.6 °C

1.6 °C = 20.4 °C/m × 1 × m

Therefore m = 1.6/20.4 = 0.0784 m

number of moles in 2.50 g of cyclohexane = 0.0784 m or 0.0784 moles of the substance in 1000 grams of cyclohexane. That is

2.5 ×0.0784/1000 moles in 2.5 graams of cyclohexane  that is

1.96 × 10⁻⁵ moles in 2.5 grams of cyclohexane

1.96 × 10⁻⁵ moles of the substance weighs 0.050 grams

Therefore 1 Mole weighs (0.05 g)/(1.96 × 10⁻⁵ moles) = 255g/mole

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kotykmax [81]
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol 
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol 
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution 
there are 1.00 mol in 1 L of solution 
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L 
volume of HCl required is 0.150 L 
3 0
2 years ago
A sample of ice is heated continuously until it becomes a liquid, and then a gas. Its temperature is recorded throughout and a g
padilas [110]

Answer:

The answer to your question is: C. The specific latent heat of fusion

Explanation:

A. The specific latent heat of vaporization  Specific latent heat of vaporization indicates the transition from liquid to vapor, but we are not looking for this definition. This answer is wrong.

B. The specific heat indicates the amount of heat needed to increase the temperature of water 1°C, so this answer is wrong.

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3 0
2 years ago
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

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Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

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3 0
2 years ago
Limestone (CaCO3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be p
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Answer: 2800 g

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 5 kg = 5000 g

\text{Number of moles}=\frac{5000g}{100g/mol}=50moles

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Mass of CaO=moles\times {\text{Molar mass}}=50moles\times 56g/mole=2800g

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3 0
3 years ago
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calories of fat = 1 g x 9 KCal/g
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to get the resualt to two significant figures 
∴ the resault is = 0.24 Cal = 240 KCal

4 0
2 years ago
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