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Marysya12 [62]
3 years ago
14

AN object has a volume of 77ml and a mass of 429. What is the density of this object?

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

4.254320865115cm or simplied 4.25cm

Explanation:

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Hurrrryyyyy pls
deff fn [24]

Answer:

The growth of the plant

Explanation:

The growth of the plant from the bean soil is the dependent variable I believe. This is because it could change depending on many factors for e.g. the amount of light or water

8 0
2 years ago
Explain why, at room temperature, CO2 is a gas and CS2 is a liquid. You may use diagrams as part of your explanation.
eduard

Explanation:

A. Hydrogen bonding is present in CS2 but not in CO2.

B. CS2 has greater dipole moment than CO2 and thus the dipole-dipole forces in CS2 are stronger.

C. CS2 partly dissociates to form ions and CO2 does not. Therefore, ion-dipole interactions are present in CS2 but not in CO2.

D. The dispersion forces are greater in CS2 than in CO2.

<u><em>PLS MARK BRAINLIEST :D</em></u>

3 0
2 years ago
A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO
NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity,  μg

            N₀ = Original quantity, μg

             λ= Decay constant day⁻¹

              t =  time in days

Since the half life is 4.5 days, we can calculate the  λ from (1) by  substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5  = -4.5λ

-0.6931 = -4.5λ

λ =   -0.6931 /-4.5

  =0.1540 day⁻¹

Substituting into (1)  we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀]   = exp (-0.154 x 1)

    5/N₀        = 0.8572

N₀  =  5/0.8572

     =    5.8329μg

    ≈     5.8μg

The Chemist must order 5.8μg  of 47-CaCO3

6 0
2 years ago
The pressure that is the difference between the net hydrostatic pressure and the net colloid osmotic pressure is called
mina [271]

The pressure calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure is known as: filtration pressure.

<h3>What is pressure?</h3>

Pressure can be defined as a measure of the force exerted per unit area of an object or body. Thus, it is usually measured in Newton per meter square.

<h3>The types of pressure.</h3>

In Science, there are different types of pressure and these include the following:

  • Hydrostatic pressure
  • Atmospheric pressure
  • Osmotic pressure
  • Filtration pressure

Filtration pressure is a pressure that is typically calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure. Also, it promotes the filtration of fluid through a membrane.

Read more on pressure here: brainly.com/question/24827501

4 0
2 years ago
Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
MrRissso [65]

Answer:

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

10^{-9,33} = [H⁺]

The volume of swimming pool is:

700'000 galllons ×\frac{3,78541 L}{1 gallon} = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

7 0
3 years ago
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