1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marysya12 [62]
3 years ago
14

AN object has a volume of 77ml and a mass of 429. What is the density of this object?

Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

4.254320865115cm or simplied 4.25cm

Explanation:

You might be interested in
Discuss two physical and two chemical properties of Nitrogen​
Zigmanuir [339]

Answer:

Nitrogen gas (chemical symbol N) is generally inert, nonmetallic, colorless, odorless and tasteless. Its atomic number is 7, and it has an atomic weight of 14.0067. Nitrogen has a density of 1.251 grams/liter at 0 C and a specific gravity of 0.96737, making it slightly lighter than air.

Explanation:

7 0
3 years ago
553.5 mL ?:cm^3<br> how do i get my answer? and what is the answer?
dmitriy555 [2]

Answer:

553.5 cm3

Reason:

1 mL = 1 cm3

6 0
3 years ago
A slurry of flakes soybeans weighing a total of 100 kg contains 75 kg of inert solids and 25 kg of solution with 10 wt% oil and
lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

F_{solution} = mass of solvent + mass of oil (i.e A+C)

<u>Feed Phase:</u>

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

 = 25kg

Mass ratio of oil to solution Y_{F} =\frac{Mass C}{Mass (A+C)}

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane  in feed = 25 ×  0.9 =22.5kg + 2.5 =25kg

therefore  Y_{F} = \frac{2.5}{25}

= 0.1

mass ratio of solid to solution Y_{A}  =  \frac{Mass A}{Mass (A+C)}=[tex]\frac{75}{25}

=3

<u>Solvent Phase:</u>

C= Mass of oil= 0(kg)

A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

solvent= 100kg

<u>Underflow:</u>

underflow = L₁ = (unknown) ???

L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = \frac{mass B}{mass(A+C)}

solution in underflow E₁ = Mass (A+C)

<u>Overflow:</u>

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75=  E₁ × N₁

75 =  E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

5 0
3 years ago
The ____________________ is done first so that you know how you want to go about your ____________________.
N76 [4]
We need a photoooooooo
8 0
2 years ago
Read 2 more answers
(6.022*10^23)*2.58=<br> what’s the answer
Sladkaya [172]
The answer would be
1.553676 \times  {10}^{24}
8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the difference between an element and a compound?
    9·2 answers
  • What does group 4 in the periodic table all have in common
    8·1 answer
  • Which term is used to describe the day of June 21 at north pole in terms of daylight and darkness
    7·1 answer
  • What is an succession? (69) points HELP!
    15·2 answers
  • Grams needed to prepare the solution
    14·1 answer
  • Determine the hydroxide ion concentration in<br> a solution that is 0.028 M NaOH.
    8·1 answer
  • What is the oxygen number of N in NO2-¹​
    12·1 answer
  • What’s the difference in the number of protons of an atom of lithium and an atom of chlorine :)) I need this answer quick
    15·1 answer
  • What is the coefficient of H2O when the following equation is properly balanced with the smallest set of whole numbers?
    15·2 answers
  • Please explain:) I would really appreciate a step by step explanation if possible.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!