Ask question

Ask question

All categories

4 years ago

5

What kind of microscope would be used to study a whole or opaque object?

1 answer:

djyliett [7]4 years ago

4 0

Answer:

the compound light microscope

Explanation:

The stereomicroscope is to study section to study the entire objects in three dimensions at low magnification. A Compound light microscope is used for small or thinly sliced objects under higher magnification than stereomicroscope.

You might be interested in

What are the advantages to a quality<br> saw?

gladu [14]

Ans: A quality handsaw makes jobs such as crosscutting moldings, cleaning out dovetails and flush cutting dowels and pegs faster, cleaner and safer. There are myriad different types and sizes of blades for working with wood and other materials.

7 0

3 years ago

stimate the force required in extruding 70-30 brass at 700C, if the billet diameter is 125 mm and the extrusion ratio is 20

Jlenok [28]

U have to find the bill it into the internet in order for me to get the answer. Also u have to make it change into the call.

7 0

3 years ago

The electron concentration in silicon at T = 300 K is given by

puteri [66]

Answer:

$E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m$

Explanation:

From the question we are told that:

Temperature of silicon $T=300k$

Electron concentration $n(x)=10^{16}\exp (\frac{-x}{18})$

$\frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})$

Electron diffusion coefficient is $Dn = 25cm^2/s \approx 2.5*10^{-3}$

Electron mobility is $\mu n = 960 cm^2/V-s \approx0.096m/V$

Electron current density $Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2$

Generally the equation for the semiconductor is mathematically given by

$Jn=qb_n\frac{dn}{dx}+nq \mu E$

Therefore

$-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E$

$E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}$

$E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m$

7 0

3 years ago

An object of mass 521 kg, initially having a velocity of 90 m/s, decelerates to a final velocity of 14 m/s. What is the change i

Harman [31]

Answer:2058.992KJ

Explanation:

Given data

Mass of object $\left ( m\right )$ =521kg

initial velocity $\left ( v_0\right )$ =90m/s

Final velocity $\left ( v\right )$ =14m/s

kinetic energy of body is given by= $\frac{1}{2}$ $m$ $v^{2}$

change in kinectic energy is given by substracting final kinetic energy from initial kinetic energy of body.

Change in kinetic energy= $\frac{1}{2}\times m$ $\left ( V_0^{2}-V^2\right )$

Change in kinetic energy= $\frac{1}{2}\times521$ $\left ( 90^{2}-14^2\right )$

Change in kinetic energy=2058.992KJ

7 0

3 years ago

What does the automobile rely on to function?

Montano1993 [528]

Answer:

fuel

Explanation:

all automobiles rely on fuel to function

3 0

3 years ago