<u>a).</u>
Kenny's potential energy at the top becomes kinetic energy at the bottom.
(M G H) = 1/2 (M V²)
Divide each side by 'M': G H = 1/2 V²
Multiply each side by 2: 2 G H = V²
Take the square root of each side: V = √(G H)
= √(9.8 x 3.2) = <em><u>5.6 m/s .</u></em>
<u>b).</u>
Notice in the solution for a). that each side of the equation was divided
by 'M'. The answer didn't depend on Kenny's mass, and it doesn't depend
on Cartman's mass either. Cartman and Kenny are both moving at the
same speed when they reach the bottom.
<u>c).</u>
Notice in the solution for a). that each side of the equation was divided
by 'M'. The answer didn't depend on Kenny's mass. It didn't depend on
Cartman's mass either, and it doesn't depend on Kyle's mass either, either.
Each of them is moving at the same speed when he reaches the bottom.
The same also applies to girls as well, too.
The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
The given parameters;
- mass of the car, m = 1400 kg
- Initial velocity of the car, u = 25 m/s
- coefficient of kinetic friction, μ = 0.7
The acceleration of the car is calculated as follows;
a = μg
a = 0.7 x 9.8
a = 6.86 m/s²
The time taken for the car to stop is calculated by using Newton's second law of motion;
F = ma
Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
Learn more here:brainly.com/question/19887955
Plant cells have eukaryotic cells which act like lysosomes
Asexual propagation involves taking a part of one parent plant and causing it to regenerate itself into a new plant. The resulting new plant is genetically identical its parent. Asexual propagation involves the vegetative parts of a plant: stems, roots, or leaves.
The most common method for asexual propagation is from cuttings. A cutting is any detached plant part which, under favorable conditions for regeneration of missing parts, will produce a new plant identical to the parent plant.
Hope that help:)
Answer:
3850 J
Explanation:
= initial volume of the gas = 30 L = 0.03 m³
= final volume of the gas = 65 L = 0.065 m³
= Constant pressure of the gas = 110 kPa = 110000 Pa
= Work done by the gas
Since the pressure is constant, Work done by the gas is given as