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alexandr1967 [171]
2 years ago
5

Objects that are not moving have NO _____. A. mass (only) B. mass and momentum (only) C. velocity and momentum (only) D. mass, v

elocity, and momentum
Physics
1 answer:
shepuryov [24]2 years ago
6 0

Answer:

Objects that are not moving have NO velocity and momentum (only)

Explanation:

This best explains the potential energy of an object, when an object is at rest. it is said to have possessed a potential energy but without velocity and momentum i.e energy at rest

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Roman55 [17]

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1. Every unit that is connected in a parallel circuit gets equal amount of voltage.

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7 0
2 years ago
Which of the following describes resistance force?
Harman [31]
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4 0
3 years ago
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Match the physical properties on the left with their descriptions on the right. 1. luster ability to dissolve in another substan
Serjik [45]

Answer :

1) Luster →  the shininess of a material

2) Freezing point → temperature at which a liquid becomes a solid

3) Viscosity → the measure of a substance's resistance to flow

4) Solubility → ability to dissolve in another substance

5) Ductility → able to be pulled into a wire

Explanation :

Luster : It is defined as the material which has the shining property.

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Viscosity : It measures the resistance of the liquids to flow .

Solubility : It is defined as the ability of a substance (solute) to dissolve into a liquid (solvent).

Ductility : It is defined as the ability of a metal into a thin wire without breaking.

7 0
3 years ago
In which situation is work being done?
Darina [25.2K]
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Can someone explain to me how to do this problem ?​
valentina_108 [34]

Answer:

The image distance is 13.3 cm  ⇒ answer B

Explanation:

* Lets study the information in the problem

- The distance between the object and the convex lens is 40.0 cm

- The lens focuses light at a distance of 10.0 cm

- The equation of the image distance is d_{i}=\frac{d_{o}f}{d_{o}-f}

 where di is the image distance, do is the object distance and f is the

 distance of the focuses lens

* Lets solve the problem

∵ do = 40.0 cm

∵ f = 10.0 cm

∵ d_{i}=\frac{d_{0}f}{d_{o}-f}

- Substitute the values of do and f in the equation

∴ d_{i}=\frac{(40.0)(10.0)}{(40.0)-(10.0)}=\frac{400.0}{30.0}=\frac{40}{3}

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* The image distance is 13.3 cm

7 0
2 years ago
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