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4 years ago

Which word describes the forces acting on the car?

Chemistry

1 answer:

KIM [24]4 years ago

7 0

C. Unbalanced describes the forces acting on the car

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Type the correct answer in the box. Express your answer to two significant figures.

Shalnov [3]

Answer:

5.8 L

Explanation:

Assuming that the hydrogen gas in the balloon acts as an ideal gas, we can solve the problem by using the equation of state for an ideal gas:

$pV=nRT$

where:

p is the pressure of the gas

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

p = 1.05 atm is the pressure

n = 0.24 mol is the number of moles

$T=35^{\circ}C+273=308 K$ is the temperature of the gas

$R=0.082 L \cdot atm\cdot mol^{-1} K^{-1}$ is the gas constant

And solving for V, we find the volume of the gas in liters:

$V=\frac{nRT}{p}=\frac{(0.24)(0.082)(308)}{1.05}=5.8 L$

8 0

4 years ago

PLEASE HELP AND EXPLAIN!Calculate the energy required to heat 187.0 g of ammonia from 36.1 °C to 52.9 °C. Assume the specific he

Alenkinab [10]

Answer:

$E=1.48x10^4J$

Explanation:

Hello!

In this case, since the energy implied in a heating process is computed by using the following equation:

$E=mC(T_f-T_i)$

Whereas m is the mass, C the specific heat and T the temperature. In such a way, by plugging in the given mass, specific heat and temperatures, we obtain the following energy:

$E=187.0g*4.703\frac{J}{g\°C} (52.9\°C-36.1\°C)\\\\E=1.48x10^4J$

Considering that the specific heat can by used by unit of °C or K because their difference is equivalent.

Regards!

3 0

3 years ago

Calculate the boiling point (in degrees C) of a solution made by dissolving 7 g of naphthalene {C10H8} in 14.4 g of benzene. The

never [62]

Answer:

The boiling point = 89.69 °C

Explanation:

Step 1: Data given

Mass of naphthalane = 7.0 grams

Mass of benzene = 14.4 grams

The Kbp of the solvent = 2.53 K/m

The normal boiling point is 80.1°C

Naphthalene, C10H8 , is a non-electrolyte, which means that the van't Hoff factor for this solution will be 1

Step 2: Calculate moles naphthalene

Moles naphthalene = mass / molar mass

Moles naphthalene = 7.0 grams / 128.17 g/mol

Moles naphthalene = 0.0546 moles

Step 3: Calculate molality

Molality = moles naphthalene / mass water

Molality = 0.0546 moles / 0.0144 kg

Molality = 3.79 molal

Step 4:

ΔT = i*Kb*m

ΔT = 1*2.53 K/m * 3.79 molal

ΔT = 9.59 °C

The boiling point = 80.1 °C + 9.59 °C = 89.69 °C

3 0

3 years ago

What is mass when density is 9.51 and volume is 9.26

zlopas [31]

Density = mass / volume

9.51 = m / 9.26

9.51 * 9.26 = m

m = 88.0626

8 0

3 years ago

Which property increases as you move down a column in the periodic table?

777dan777 [17]

Answer:

I think it's c have a good day

7 0

3 years ago

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