Answer:
Potassium sulfate
Explanation:
I searched it up on the internet
Can I please have a brainliest
1. Physical matter
2. Chemical matter
3. Physical matter
4. Physical matter
5. Chemical matter
6. Physical matter.
First M stands for Molarity which is (moles of solute) / (Liters of solution). we also know that moles = (mass) / (molar mass). so we can form some equations here. We know:
Molarity (M) = moles (mol) / Liters (L)
moles (mol) = (mass) / (molar mass)
we can substitute the (mass) / (molar mass) for (moles) and get:
M = [(mass) / (molar mass)] / Liters
we can now isolate mass and get
M * Liters * molar mass = mass
now we need to find the molar mass of CaCl2 which is 110.98 g/mol
plug the values in and get
.350M * 6.5L * 110.98 g/mol = mass
mass = 252.4795g however the 6.5L has only 2 sig figs so i would say
mass CaCl2 = 2.5 * 10 ^2 g
Answer:
DO NOT TASTE IT, but all the rest are correct
Explanation:
Answer : The value of 
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
![[ATP]](https://tex.z-dn.net/?f=%5BATP%5D)
= 5.0 mM
![[ADP]](https://tex.z-dn.net/?f=%5BADP%5D)
= 0.60 mM
![[HPO_4^{2-}]](https://tex.z-dn.net/?f=%5BHPO_4%5E%7B2-%7D%5D)
= 5.0 mM
Now put all the given values in this expression, we get
Now we have to calculate the value of .
The formula used for is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -49.6 kJ/mol
