Recall that the value of Kw for the autoionization of water varies with temperature. At the temperature of your body (37°C), Kw = 3.98 x 10-14 rather than 1.00 x 10-14. What is the pH of pure water at 37°C?
1 answer:
Answer:
pH =6.70
Explanation:
When Kw = 1x10^-14
[H3O+] = [OH-] --> 1x10-7
Kw =3.98x^10-14
3.98x^10-14 = [H3O+] . [OH-]
√ (3.98x^10-14) = [H3O+] = [OH-]
[H3O+] = 1.99×10^-7
- log [H3O+] = pH ---> -log 1.99x10^-7 = 6.70
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