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Marysya12 [62]
4 years ago
8

Recall that the value of Kw for the autoionization of water varies with temperature. At the temperature of your body (37°C), Kw

= 3.98 x 10-14 rather than 1.00 x 10-14. What is the pH of pure water at 37°C?
Chemistry
1 answer:
kvasek [131]4 years ago
5 0

Answer:

pH =6.70

Explanation:

When Kw = 1x10^-14

[H3O+] = [OH-] --> 1x10-7

Kw =3.98x^10-14

3.98x^10-14 = [H3O+] . [OH-]

√ (3.98x^10-14) =  [H3O+] = [OH-]

[H3O+] = 1.99×10^-7

- log [H3O+] = pH ---> -log 1.99x10^-7 = 6.70

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What is meniscus ? why is it necessary to know about it when measuring liquids quizzlet?
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6 0
3 years ago
Read 2 more answers
Ain___accepts electrons and becomes___
Serga [27]

<u>Answer:</u>

<em>An atom accepts electrons and becomes an anion.</em>

<em></em>

<u>Explanation:</u>

Atomic number = number of electrons = number of protons.

Atomic number of sodium is 11

So the atom contains 11 protons and 11 electrons

To find the number of neutrons we make use of the formula  

Mass number - atomic number = number of neutrons

From the periodic table, we know mass number of sodium is 23

So number of neutron = 23 - 11 = 12.

When a sodium atom loses an electron it will have 11 positive protons and 10 negative electrons. Since 1 positive charge is more, Na becomes Na^+.

Positively charged ion is called as cation

Chlorine's atomic number is 17 so it has 17 protons and 17 electrons.

When it gains an electrons, it will have 17 positive protons and 18 negative electrons. Since 1 negative charge is more, Cl becomes Cl^-.

Negatively charged ion is called as anion.

3 0
3 years ago
A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium
xz_007 [3.2K]

Answer:

A. Theoretical yield of CaO is 11.59 g

B. Percentage yield of CaO = 58.76%

Explanation:

The following data were obtained from the question:

Mass of CaCO₃ = 20.7 g

Actual yield of CaO = 6.81 g

Theoretical yield of CaO =?

Percentage yield of CaO =?

The equation for the reaction is given below:

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (3×16)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

A. Determination of the theoretical yield of CaO.

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 20.7 g of CaCO₃ will decompose to produce =

(20.7 × 56)/100 = 11.59 g of CaO.

Thus, the theoretical yield of CaO is 11.59 g

B. Determination of the percentage yield.

Actual yield of CaO = 6.81 g

Theoretical yield of CaO = 11.59 g

Percentage yield of CaO =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 6.81/11.59 × 100

Percentage yield of CaO = 58.76%

4 0
3 years ago
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