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3 years ago

Mercury is in the 80th position in the periodic table. How many protons does it have?

Physics

2 answers:

ipn [44]3 years ago

3 0

Number of Protons = Atomic number = 80

so, Mercury has 80 protons...

Lera25 [3.4K]3 years ago

3 0

Answer: 80

Explanation:

Elements are arranged in periodic table in order of increasing atomic number.

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons

Mercury (Hg) is a d block element and its atomic number is 80, thus it contains 80 protons and 80 electrons.

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

Electronic configuration of mercury in terms of noble gas configuration is $[Xe]4f^{14}5d^{10}6s^{2}$ .

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Lauryn serves a volleyball with a mass of 2.1 kg. The ball leaves her hand with a speed of 30 m/s.

Naya [18.7K]

Hi! Let's see.

<h3>TOPIC: Kinetic Energy.</h3>

Explanation:

Data:

Mass(m) = 2.1 kilograms
Speed(v) = 30 m/s
Kinetic Energy(Ek) = ?

==================================================================

Use the kinetic energy formula:

$\boxed{\boxed{\bold{E_{k}=\frac{m*(v)^{2}}{2}}}}$

Replace by the data:

$\boxed{E_{k}=\frac{2.1kg*(30\frac{m}{s})^{2}}{2}}}}}$

We multiply speed squared:

$\boxed{E_{k}=\frac{2.1kg*900\frac{m}{s}}{2}}}$

Multiply in the numerator, without forgetting the units:

$\boxed{E_{k}=\frac{1890J}{2}}}}$

Both numerator and denominador operations are divided:

$\boxed{\bold{E_{k}=945\ J}}$

Answer: The kinetic energy is 945 Joules.

Cordially Alejanndraax. Greetings!

8 0

3 years ago

A girl with a mass of 27 kg is playing on a swing. There are three main forces

N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

Mass of the girl, m = 27 kg
Speed of the girl, v = 3 m/s
Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

$T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N$

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0

2 years ago

An object carries a +15.5 uC charge.

abruzzese [7]

Answer:

3.67 N

Explanation:

From the question given above, the following data were obtained:

Charge of 1st object (q₁) = +15.5 μC

Charge of 2nd object (q₂) = –7.25 μC

Distance apart (r) = 0.525 m

Force (F) =?

Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:

For the 1st object

1 μC = 1×10¯⁶ C

Therefore,

15.5 μC = 15.5 × 1×10¯⁶

15.5 μC = 15.5×10¯⁶ C

For the 2nd object:

1 μC = 1×10¯⁶ C

Therefore,

–7.25 μC = –7.25 × 1×10¯⁶

–7.25 μC = –7.25×10¯⁶ C

Finally, we shall determine the force. This can be obtained as follow:

Charge of 1st object (q₁) = +15.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.25×10¯⁶ C

Distance apart (r) = 0.525 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²

F = 3.67 N

Therefore, the force on the object is 3.67 N

4 0

3 years ago

What is the difference in the speed of the generator with a small magnet and a generator with a large magnet?

Delvig [45]

With a small magnet with a generator it will be taken up quickly because how small it is while with a big generator it would take more force for it for the generator to attach because the larger the magnet that heavier it will be because it is attached to the North Pole magnet

8 0

3 years ago

Read 2 more answers

With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the botto

Dvinal [7]

The speed of the car at the bottom of the hill is obtained as, $v = \sqrt{2gh}$

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

$K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}$

where;

v is the speed of the car at the bottom of the hill
h is the height of the hill
g is acceleration due to gravity

Thus, the speed of the car at the bottom of the hill is obtained as, $v = \sqrt{2gh}$

Learn more about conservation mechanical energy here: brainly.com/question/332163

3 0

3 years ago