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Allisa [31]
3 years ago
10

Consider a 150-w incandescent lamp. the filament of the lamp is 5-cm long and has a diameter of 0.5 mm. the diameter of the glas

s bulb of the lamp is 8 cm. determine the heat flux, in w/m2, (a) on the surface of the filament and (b) on the surface of the glass bulb, and (c) calculate how much it will cost per year to keep that lamp on for eight hours a day every day if the unit cost of electricity is $0.08/kwh.
Physics
1 answer:
Allisa [31]3 years ago
8 0
<span>(a).the heat trasfer surface area and heat flux on the surface of filament are Area of Surface= µDL=3.14(0.05cm)(5cm)= 0.785 cm square qs=Q/Area of surface= 150W/0.785= 191W/cmsq.=1.91x10³x10³W/Msq (b). the heat surface on the surface of heat bulb Area of surface = 3.14xD²= 3.14(8CM)²= 201.1cm² qs=Q/Area of surface=150w/201.1cm²=0.75 w/cm²= 7500w/m² the amount and cost of electrical energy consumed during one period is Electrical Consumption=QΛt=(0.15 KW)(365X8h/yr)=438 k Wh/yr Annual cost= 438 kWh/yr)($.08/kWh)= $ 35.04 /yr</span>
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Max ang. speed(u) = 18 rad/s
final ang. speed(v) = 0
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3 years ago
A war wolf is a device used during the middle ages to assault fortifications with large rocks. A simple trebuchet is constructed
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Answer:v=41.23 m/s

Explanation:

Given

mass of heavy object m_1=52 kg

distance of m_1 from the axle r_1=14 cm

mass of rock m_2=123 gm

Length of rod =4.1 m

distance of m_2 from axle r_2=4.1-0.14=3.96 m

Net torque acting is

T_{net}=m_1gr_1-m_2gr_2

T_{net}=52\times 0.14\times g-0.123\times 3.96\times g

T_{net}=6.793\times 9.8

T_{net}=66.57 N-m

Work done by T_{net} is converted to rock kinetic Energy

thus

T_{net}\times \theta =\frac{mv^2}{2}

Where \theta =angle\ turned =\frac{\pi }{2}

v= velocity\ at\ launch

66.57\times \frac{\pi }{2}=\frac{0.123\times v^2}{2}

v^2=66.57\times \pi

v=\sqrt{1700.511}

v=41.23 m/s

3 0
3 years ago
A 70 kilogram hockey player skating east on an ice rink is hit by a 0.1 kilogram hockey puck moving toward the west. The puck ex
guajiro [1.7K]

Given:

70 Kilogram hockey

Hit by 0.1 kilogram

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Description:

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Hope this helps.

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Kirchhoff's circuit laws are two equalities that deal with the current and potential difference (commonly known as voltage) in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of Maxwell.

6 0
3 years ago
The period of rotation of Mars is 1 day and 37 minutes. Determine its frequency of rotation in Hertz.
Sholpan [36]

The frequency of rotation of Mars is 0.0000113 Hertz.

<u>Given the following data:</u>

  • Period = 1 day and 37 minutes.

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

<u>Conversion:</u>

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1477 minute = X seconds

Cross-multiplying, we have:

X = 60 × 1477

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Now, we can find the frequency of rotation of Mars by using the formula:

Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}

<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

Read more: brainly.com/question/14708169

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