Molarity of Vinegar solution is 0.107 M
<u>Explanation:</u>
Let V1 be the volume of NaOH = 13.58 ml
Let V2 be the volume of Vinegar = 14.66 ml
Let M1 be the molarity of NaOH = 0.115 M
Let M2 be the molarity of Vinegar = ?
Using the Law of Volumetric analysis, V1M1= V2M2
Rearranging the equation to get M2 as,
M2 = V1M1/V2 = 13.58 ml * 0.115 M/14.66 ml = 0.107 M
So the Molarity of Vinegar = 0.107 M
Answer:
Ernest Z. The molarity and mass percent of the vinegar are 0.8393 mol/L and 5.010 %.
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