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Nikolay [14]
3 years ago
14

What is the heat needed to raise the temperature of 24.7 kg silver from 14.0 degrees Celsius to 30.0 degrees Celsius? Specific h

eat capacity of silver is 236 J/(kg * C°)
Chemistry
1 answer:
ELEN [110]3 years ago
8 0

Answer:

Q=93.3kJ

Explanation:

Hello,

In this case, by knowing that the heat due to a change of temperature is given by:

Q=mCp\Delta T

Whereas Q accounts for the heat, m for the mass, Cp the heat capacity and ΔT for the change in temperature. In such a way the required heat results:

Q=24.7kg*236\frac{J}{kg^oC}*(30.0-14.0)^oC*\frac{1kJ}{1000J} \\Q=93.3kJ

Best regards.

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Answer :

The time taken by the reaction is 19.2 seconds.

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Explanation :

The general formula to determine the unit of rate constant is:

(Concentration)^{(1-n)}(Time)^{-1}

Unit of rate constant                           Order of reaction

Concentration/Time                                        0

Time^{-1}                                                              1

(Concentration)^{-1}Time^{-1}                                 2

As the unit of rate constant is M^{-1}min^{-1}. So, the order of reaction is second order.

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

where,

k = rate constant = 1.95M^{-1}s^{-1}

t = time = ?

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[A_o] = initial concentration = 2.48 M

Now put all the given values in the above expression, we get:

1.95\times t=\frac{1}{0.97}-\frac{1}{2.48}

t=0.32min=0.32\times 60s=19.2s

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8 0
3 years ago
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Explanation:

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<em>Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.</em>

<em />

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<h3>K = 0.5</h3>
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