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Margaret [11]
3 years ago
14

Use the periodic table to identify the molar mass of each element below. Answer without doing any calculations.

Chemistry
2 answers:
Delicious77 [7]3 years ago
8 0

Answer:

Beryllium (Be) : 9.01 g/mol

Silicon (Si) : 28.09 g/mol

Calcium (Ca) : 40.08 g/mol

Rhodium (Rh) : 102.91 g/mol

Explanation:

prisoha [69]3 years ago
4 0

Answer:

Beryllium (Be) : 9.01 g/mol

Silicon (Si) : 28.09 g/mol

Calcium (Ca) : 40.08 g/mol

Rhodium (Rh) : 102.91 g/mol

Explanation:

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tino4ka555 [31]

The biological risk for the first person than the second as a result of radiation weighting is 10 times.

<h3>What is radiation weighting factor?</h3>

As stated in the question, radiation weighting factor (q) is the ability to transfer energy to the body.

If radiation factor of proton = 2, and radiation factor of alpha particles = 20.

  • First person is exposed to alpha radiation = 20
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Risk of first person with respect to second person = 20/2 = 10 times higher

Learn more about radiation factor here: brainly.com/question/24039736

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2 years ago
Select the correct use of the compound tms in nmr spectroscopy.a. it is a signal-to-noise enhancerb. it is an internal standard
SpyIntel [72]

TMS stands for Tetramethylsilane

Formula : Si(CH₃)₄

It is used as internal standard for chemical shift

In TMS all the four methyl groups are similar thus all the 12 hydrogen are chemically equivalent. They will show proton NMR at same level and which will appear as a singlet.

We have defined this singlet to be as reference set as zero.

Generally the other organic compounds show chemical shift downfield.So have positive chemical shift with respect to TMS shift.

8 0
3 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

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These two elements are most likely good conductors of heat and electricity and shiny when solid.
Mama L [17]
Copper and Aluminium..........
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3 years ago
Read 2 more answers
In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are
zimovet [89]

Answer:

-6.4x10⁻¹⁹ C

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