Answer:
They are different ions of the same element.
Explanation:
on Quizlet
Answer:
the answer of this question is 0.000058
Introduction
empirical formula
A table of values shows a list of the values for an independent variable, x, matched with the value of the dependent variable, y. In many cases, an equation can be used to relate the two values. If you know the equation, you can easily generate a table of values.
If you are given the table of values, you must determine how the two values are related and then write an equation that shows the relationship.
xy-2-1-100112When looking at the relationship between the y-values and the x-values, it's easy to see that each y-value is 1 more than the x-value. Therefore, the equation that describes this relationship is y = x + 1.
Develop a Rule When Given a Table of Values
Writing an Equation for a Table of Values
Look at the table below. There does not appear to be a constant rate of change.

In this example, we look at the ratio of the change in the pattern of y-values and x-values.




Even though there did not appear to be a constant rate of change, there is actually a constant rate of change of 2.
We're almost ready to write our equation.
We now know the value for m (the slope) in the equation y = mx + b is 2. Since m is 2, we know that each x-value is being multiplied by 2.
What else is happening to the x-value to get the corresponding y-value?
xProcessy-32(-3) + 3-3-12(-1) + 3132(3) + 3962(6) + 31572(7) + 317
We also need to add 3 to the product in order to get the corresponding y-value.
The equation that represents this table of data is y = 2x + 3.
Answer:
The molar mass of Barium Oxide, BaO is 153.33g/mol.
Explanation:
The molar mass of a compound is defined as the sum of the relative atomic mass of the atoms which forms the chemical compound.
The atomic mass of Barium Ba = 137.33
Atomic mass of Oxygen O = 16.00
Adding the respective atomic mass together we have;
BaO = 137.33 + 16.00
BaO=153.33g/mol.
So therefore, the molar mass of Barium Oxide BaO is 153.33g/mol.
