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3 years ago

Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide.

Chemistry

1 answer:

serg [7]3 years ago

7 0

2HNO3 + Ca(OH)2 --> 2HOH + Ca(NO3)2

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How many moles of carbon dioxide are present in 14g of co2

Tomtit [17]

0.32 moles

You just do 14/ 44.01 (the atomic mass of carbon + oxygen's atomic massX2)

8 0

3 years ago

Precision Problems:

Lorico [155]

Answer:

$Precision = 2.70 \± 0.1\ cm$

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

$Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm$

$Mean = \frac{18.9}{7}\ cm$

$Mean = 2.70\ cm$

Step 2: Get The Range

$Range = Highest - Lowest$

$Range = 2.80cm - 2.60cm$

$Range = 0.2\ cm$

Step 3: Divide Range by 2

$Approximate\ Range = \frac{1}{2}Range$

$Approximate\ Range = \frac{1}{2} * 0.2\ cm$

$Approximate\ Range = 0.1\ cm$

Step 4: Determine the Precision

$Precision = Average \± Approximate\ Range$

Substitute 2.70 for Average and 0.1 for Approximate Range

$Precision = 2.70 \± 0.1\ cm$

4 0

3 years ago

How do i found out how animals gain energy and from where

otez555 [7]

Answer:

Animals gain energy from the food they eat. Some animals eat plants while others eat other animals. This is passing of energy from the sun to plants to animal to other animals is called a food chain

6 0

3 years ago

What is the method of harvesting trees where mature trees are left intact that

Arte-miy333 [17]

Hey day is the method of harvesting tress.

8 0

2 years ago

A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts

Arlecino [84]

Answer : The age of the artifact is, $2.54\times 10^3\text{ years}$

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{5715\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant = 58.2 counts per minute

a - x = activity left after decay process = 42.8 counts per minute

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{58.2}{42.8}$

$t=2540.5\text{ years}=2.54\times 10^3\text{ years}$

Therefore, the age of the artifact is, $2.54\times 10^3\text{ years}$

4 0

3 years ago