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3 years ago

Can someone provide me with 5 different sentences describing what the boundry type Divergent - Mid-Ocean Ridge is? 10 POINTS!!

Chemistry

1 answer:

Lorico [155]3 years ago

4 0

Answer:

The massive mid-ocean ridge system is a continuous range of underwater volcanoes that wraps around the globe like seams on a baseball, stretching nearly 65,000 kilometers (40,390 miles).

The majority of the system is underwater, with an average water depth to the top of the ridge of 2,500 meters (8,200 feet).

Mid-ocean ridges occur along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart.

As the plates separate, molten rock rises to the seafloor, producing enormous volcanic eruptions of basalt.

The speed of spreading affects the shape of a ridge – slower spreading rates result in steep, irregular topography while faster spreading rates produce much wider profiles and more gentle slopes.

tell me if this is wrong please

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Calculate the given mass in 0.5 mol. Of CH4

xz_007 [3.2K]

Answer:

8 grams

Explanation:

The molar mass of CH4 is about 16 grams per mol. So you get the answer by mutlitplying 0.5 by 16, (cancel out moles by placing 1 on the bottom of the fraction).

3 0

3 years ago

Read 2 more answers

g An oxidized silicon (111) wafer has an initial field oxide thickness of d0. Wet oxidation at 950 °C is then used to grow a thi

77julia77 [94]

Answer:

Explanation:

From the information given:

oxidation of oxidized solution takes place at 950° C

For wet oxidation:

The linear and parabolic coefficient can be computed as:

$\dfrac{B}{B/A} = D_o \ exp \Big [\dfrac{-\varepsilon a}{k_BT} \Big]$

Using $D_o$ and $E_a$ values obtained from the graph:

Thus;

$\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr$

$B= 386 \ exp \Big [-\dfrac{0.78}{8.617 \times 10^{-3} \times 1173} \Big] \\ \\ = 0.1719 \ \mu m^2/hr$

So, the initial time required to grow oxidation is expressed as:

$t_{ox} = \dfrac{x}{B/A}+ \dfrac{x^2}{B} - t_o (initial)$

$where; \\ \\ t_{ox} = 2 \ hrs;\\ \\ x = 0.5 \\ \\ B/A = 0.2535 \\ \\ B = 0.1719$

∴

$2= \dfrac{0.5}{0.2535}+ \dfrac{0.5^2}{0.1719} - t_o (initial)$

$2 = 3.4267 - t_o (initial) \\ \\ t_o(initial) = 3.4267 - 2 \\ \\ t_o(initial) = 1.4267 \ hr$

NOW;

$1.4267 = \dfrac{d_o}{0.2535} + \dfrac{d_o^2}{0.1719} \\ \\ 1.4267 = 3.9448 \ d_o + 5.8173 \ d_o^2 \\ \\ d_o^2 + 0.6781 \ d_o = 0.2453$

$d_o = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$

$d_o = \dfrac{-(0.6781) \pm \sqrt{(0.6781)^2-4(1)(-0.245)}}{2(10)}$

$d_o = \dfrac{-(0.6781) \pm \sqrt{0.45981961+0.98}}{20}$

$d_o = \dfrac{-(0.6781) \pm \sqrt{1.43981961}}{20}$

$d_o = \dfrac{-(0.6781) + \sqrt{1.43981961}}{20} \ OR \ \dfrac{-(0.6781) - \sqrt{1.43981961}}{20}$

$d_o =0.02609 \ OR \ -0.0939$

Thus; since we will consider the positive sign, the initial thickness $d_o$ is ;

≅ 0.261 μm

3 0

3 years ago

What is the Celsius temperature of 1 mole of a gas that has an average kinetic energy of 3,866 joules?

Anna [14]

Temperature can be calculated using the average kinetic energy. The ideal gas equation is being related to the average molecular kinetic energy.

PV = nRT
PV = (2/3) N(0.5mv^2)

By substituting and simplifying, we eventually get the equation.

KE = (3/2)RT
T = 3866 x 2 / 8.3145 x 3 = 309.98 K or 36.83 degrees Celsius

6 0

4 years ago

What is the partial pressure of radon if the total pressure is 780 torr and the

Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure = 780torr

Partial pressure of water vapor = 1.0atm

Unknown:

Partial pressure of radon = ?