All categories

2 years ago

A solution of HCl with a volume of 25.00 mL is titrated to the endpoint, with 0.250 M

Chemistry

1 answer:

kirill [66]2 years ago

8 0

Answer:

$0.3456\ \text{M}$

Explanation:

$V_1$ = Volume of NaOH = 34.56 mL

$V_2$ = Volume of HCl = 25 mL

$M_1$ = Concentration of NaOH = 0.25 M

$M_2$ = Concentration of HCl

When endpoint is reached the number of moles of NaOH will be equal to the number of moles of HCl

$M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{0.25\times 34.56}{25}\\\Rightarrow M_2=0.3456\ \text{M}$

Concentration of HCl is $0.3456\ \text{M}$ .

You might be interested in

1)¿Como estoy siendo responsable con el cuidado de mi salud y de los demás , ya sea en casa o si algo a realizar alguna activida

erica [24]

Answer:

The most effective strategy to control the spreading of some infections is through social distancing.

Explanation:

Since we don't have an effective treatment to stop the infection of some pathogens including the recent pandemic SARS-Cov 2 virus, it is imperative to prevent it from spreading

4 0

3 years ago

A certain radioactive element has a half-life of one hour. If you start with 40.0 grams of the element at noon, how much of the

Tpy6a [65]

If you start with 40.0 grams of the element at noon, 10.0 grams radioactive element will be left at 2 p.m. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0

2 years ago

Read 2 more answers

Under conditions of "feasting", the body favors oxidation/utilization of which source for energy production

mezya [45]

During feasting, there is an increase in the supply of carbohydrates, fats and proteins in the body. Since these macronutrients are in excess, carbohydrates and proteins are utilized or oxidized as a source for energy production. On the otherhand, fats are accumulated as the rate of oxidation of this source does not increase during feasting.

4 0

3 years ago

Read 2 more answers

Someone please help me

Fudgin [204]

The answer is ultraviolet

6 0

2 years ago

spontaneous redox reaction happens between zinc (Zn) and magnesium (Mg) in an electrochemical cell. (6 points) i. Use the reduct

aev [14]

Answer:

For (i): Magnesium is getting oxidized and zinc is getting reduced.

For (ii): The half reactions are given below.

For (iii): Magnesium will act as anode and zinc act as cathode.

Explanation:

For (i):

$E^o_{(Mg^{2+}/Mg)}=-2.37V\\E^o_{(Zn^{2+}/Zn)}=-0.76V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, zinc will always undergo reduction reaction will get reduced.

Magnesium will undergo oxidation reaction and will get oxidized.

For (ii):

Oxidation reaction is defined as the reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

Oxidation half reaction: $Mg\rightarrow Mg^{2+}+2e^-$

Reduction half reaction: $Zn^{2+}+2e^-\rightarrow Zn$

For (iii):

Oxidation reaction always occurs on anode side and thus, magnesium is acting as anode.

Reduction reaction always occurs on cathode side and thus, zinc is acting as cathode.

3 0

3 years ago