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Gelneren [198K]
3 years ago
13

A solution of HCl with a volume of 25.00 mL is titrated to the endpoint, with 0.250 M

Chemistry
1 answer:
kirill [66]3 years ago
8 0

Answer:

0.3456\ \text{M}

Explanation:

V_1 = Volume of NaOH = 34.56 mL

V_2 = Volume of HCl = 25 mL

M_1 = Concentration of NaOH = 0.25 M

M_2 = Concentration of HCl

When endpoint is reached the number of moles of NaOH will be equal to the number of moles of HCl

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{0.25\times 34.56}{25}\\\Rightarrow M_2=0.3456\ \text{M}

Concentration of HCl is 0.3456\ \text{M}.

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