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4 years ago

You have a 16-kg suitcase. what work did you do when you have slowly lifted it 0.80 m upward?

1 answer:

8 0

The formula is:
Work = Force · Displacement
F = m · g
F = 16 kg · 9.8 m/s² = 156.8 N
and we know that:
d = 0.8 m
W = 156.8 N · 0.8 m = 125.44 J
Answer:
W = 125.44 J.

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Using the force table, components of a vector can be found experimentally by suspending masses from 2 orthogonal strings which o

SCORPION-xisa [38]

Answer: 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).

Explanation:

1) Since the mass of 155 g is suspended at 210 degrees, you need to find the components of its weight on the orthogonal coordinate system (0° and 90°).


2) You do that using the trignometric ratios sine and cosine.


Weight is mass × g.

Weight of the object = 155g × g

Angle, α = 210°


Horizontal component (0°)

cosα = horizontal / hypotenuse ⇒ horizontal = hypotenuse × cosα

⇒ horizontal = 155g × g × cos(210°) = - 134.23g × g

Vertical component
sinα = vertical / hypotenuse ⇒ vertical = hypotenuse × sinα
⇒ vertical = 155g × g × sin(210°) = -77.5g × g

3) Conclusion:

Therefore, the masses that must be suspended to balance the forces of the 155g mass are 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).

8 0

3 years ago

The Passage states " the cooler lake waters suppress cloud development.... " because the water cools the air above it's surface.

4vir4ik [10]

The major source of cloud development is the water vapours from the surface of huge reservoirs like lakes. Vapours do not form when the water is cold. Water evaporates only when the surfave of the water is hot. And the vapours go into the atmosphere and condense to form clouds. Without vapours,there will be no clouds.

5 0

3 years ago

Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.30 kg and is initially moving to t

snow_lady [41]

Answer:

a) 3.632 m/s

b) 0.462 m/s

Explanation:

Using the law of conservation of momentum:

$m_{1} u_{1} + m_{2} u_{2}= m_{1} V_{1} + m_{2} V_{2}$ ..........(1)

$m_{1} = 0.30 kg\\u_{1} = 2.4 m/s\\m_{2} = 0.80 kg\\u_{2} = 0 m/s$

Substituting the above values into equation (1) and make V2 the subject of the formula:

$0.3(2.4) + 0.80(0)= 0.3 V_{1} + 0.8 V_{2}\\$

$V_{2} = \frac{0.72 - 0.3 V_{1}}{0.8}$ ..................(2)

Using the law of conservation of kinetic energy:

$0.5m_{1} u_{1} ^{2} + 1.2 = 0.5m_{1} V_{1} ^{2} + 0.5m_{2} V_{2} ^{2}\\0.5(0.3) (2.4) ^{2} + 1.2 = 0.5(0.3) V_{1} ^{2} + 0.5(0.8)V_{2} ^{2}\\$

$2.064 = 0.15 V_{1} ^{2} + 0.4V_{2} ^{2}$ .......(3)

Substitute equation (2) into equation (3)

$2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.72 - 0.3V_{1} }{0.8}) ^{2}\\2.064 = 0.15 V_{1} ^{2} + 0.4(\frac{0.5184 - 0.432V_{1} + 0.09V_{1} ^{2} }{0.64}) \\1.32096 = 0.096 V_{1} ^{2} + 0.20736 - 0.1728V_{1} + 0.036V_{1} ^{2} \\0.132 V_{1} ^{2} - 0.1728V_{1} - 1.1136 = 0\\V_{1} = 3.632 m/s$

Substituting $V_{1}$ into equation(2)

$V_{2} = \frac{0.72 - 0.3 *3.632}{0.8}\\V_{2} = \frac{0.72 - 0.3 *(3.632)}{0.8}\\V_{2} = 0.462 m/s$

8 0

3 years ago

Which is an example of the conversion of gravitational potential energy into kinetic energy? a sliding hockey puck an idling car

Taya2010 [7]

A falling raindrop.

The reason why it's because mass of a raindrop is under influence of gravity pushing it down towards earth surface. When it hit the surface kinetic energy is released.

8 0

3 years ago

Read 2 more answers

the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t

Eddi Din [679]

Mass will remain constant on both planet, let mass of the object be "m".
let x be the acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is acceleration due to gravity on the surface of earth
⇒350 = m * 9.8
⇒m = 350 / 9.8 .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134 = m * x .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x = (134 * 9.8) / 350
⇒ x = 3.572 m/s²

7 0

4 years ago