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Temka [501]
3 years ago
10

You have a 16-kg suitcase. what work did you do when you have slowly lifted it 0.80 m upward?

Physics
1 answer:
Anna71 [15]3 years ago
8 0
The formula is:
Work = Force · Displacement
F = m · g
F = 16 kg · 9.8 m/s²  = 156.8 N
and we know that:
d = 0.8 m
W = 156.8 N · 0.8 m = 125.44 J
Answer:
W = 125.44 J.
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If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

5 0
3 years ago
Can somebody please help?
DedPeter [7]

Answer:

Im not sure

Explanation:

I don't take physics cuz im in 9th grade. so. idk but I will find out and come back with an answer.

7 0
3 years ago
A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
irinina [24]

288.51 N is  the magnitude of the force that the beam exerts on the hi.nge.

Given

Mass 0f beam = 40 Kg

The horizontal component of the force exerted by the hi_nge on the beam is 86.62 N

Angle between the beam and cable is = 90°

Angle between beam and the horizontal component = 31°

As the system of the beam, hi_nge and cable are in equilibrium.

The magnitude of the force that the beam exerts on the hi_nge can be calculated by -

F =The  horizontal component of force + the vertical component of force  

F = 86.62 N + 40 × 9.8 × sin 31°

F =86.62 N + 201.89 N

F = 288.51 N

Hence, the magnitude of the force that the beam exerts on the hi_nge is 288.51  N.

Learn more about components of forces here brainly.com/question/26446720

#SPJ1

7 0
2 years ago
A notebook sitting on a desk has 19 j of potential energy. What is the total mechanical energy of the notebook?
Alex17521 [72]

The total mechanical energy of the notebook is <u><em>19J</em></u>.

Mechanical energy is the sum of potential energy and kinetic energy.  It has no kinetic energy, because it's not moving.  So its potential energy is all the  mechanical energy it has.

3 0
3 years ago
Read 2 more answers
Starting from rest, a boat increases its speed to 4.12 m/s with constant acceleration. (a)
Gemiola [76]

Answer:

initial velocity = 0 m/s

final velocity = 4.92 m/s

constant acceleration so,

(a) average velocity =

(initial velocity + final velocity)/2

(b) distance = average velocity x time

substitute and calculate

Explanation:

HOOE ITS HELP ;)

7 0
2 years ago
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