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Inga [223]
3 years ago
8

Which of the following elements in group 1 of the periodic table has the smallest atomic radius?

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0
The element in group 1 of the periodic table that had the smallest atomic radius is A. Lithium.
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In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol).Calculate the number of moles of chlo
sveticcg [70]
1 mole = 70.9
X mole = 140
X=1.9746 moles
X= 1.98 when rounded to 3 significant figures.
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3 years ago
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HCL is pure covalent compound but soluble in solvent water why​
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Answer:

HCl is a polar covalent compound, because of electronegativity difference between Cl(3.5) and hydrogen (2). Hence in this way, the bond between HCl breaks and they formed ions in the polar solvent like water .

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3 years ago
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Suppose a sodium hydroxide solution was standardized against pure solid primary standard grade KHP. If 0.4798 g of KHP required
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Answer:

The NaOH solution has a molarity of 0.052 M

Explanation:

<u>Step 1:</u> Data given

Mass of KHP = 0.4798 grams

Volume of NaOH= 45.22 mL = 0.04522 L

Molar mass of NaOH = 40 g/mol

Molar mass of KHP = 204.22 g/mol

<u>Step 2</u>: Calculate moles of KHP

Moles KHP = mass KHP / Molar mass KHP

Moles KHP = 0.4798 grams / 204.22 g/mol

Moles KHP = 0.00235 moles

<u>Step 3</u>: Calculate moles of NaOH

KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles

<u>Step 4: </u>Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume NaOH

Molarity NaOH = 0.00235 moles / 0.04522 L

Molarity NaOH = 0.052 M

The NaOH solution has a molarity of 0.052 M

6 0
4 years ago
5. When sodium, a metal, is added to water, it reacts vigorously to form two new substances
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A. It is the reaction of an alkali metal with water.
B. Hydrogen , the test for hydrogen goes out with a squeaky pop.
C. Sodium + water —> sodium hydroxide + hydrogen
3 0
2 years ago
In which of the following situations is the greatest amount of work accomplished?
Dahasolnce [82]

<span>work = force x distances </span>

<span>A - moving 2 newton's up 0.6 meter = 1.2 joules
B - moving 4 newton's up 0.6 meter = 2.4 joules
C - moving 6 newton's up 0.3 meter = 1.8 joules
D - moving 9 newton's up 0.3 meter = 2.7 joules
The greatest amount of work is in example D. 
</span>

<span>
 D is your answer. </span>

7 0
3 years ago
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