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3 years ago

Draw the Lewis structure for the trisulfur molecule. Be sure to include all resonance structures that satisfy the octet rule.

Chemistry

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

Explanation:

Definition of Lewis structure is a drawing of a molecule that illustrates the connectivity of the compound, as well as identifying the lone pairs of electrons available for bonding with other molecules. Lines between atoms in a Lewis structure represent covalent bonds and lone pair electrons are drawn as a pair of dots.

Rules for drawing lewis dot structure

1. Count the number of valence electron each atom brings into the molecule Trisulfur

S3 = 6 valence electron X 3 = 18 valence electron

2. Put the electron pairs about each atom such that there are 8e- around each atom (octet rule)

with exception of H, which is only surrounded by 2e- . Sometimes it’s necessary to form double

and triple bonds. Only the elements C, N, O,P and S will form double and triple bonds.

3. If there is not enough e- to follow the octet rule then the least electronegative atom is left

short of e-

4. If there are too many e- to follow the octet rule, then the extra 8e- are placed on the central atom.

Definition of resonance: this is a way of describing bonding in certain molecules or ions by the combination of several contributing structures into a resonance hybrid in valence bond theory

Conclusion: The lewis structure is shown in the attached picture below, including the lewis dots and the resonance structure also satisfy the octet rule.

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Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

$V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}$

Solving for the molarity of base we've got:

$M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L$

Now, we can compute the moles of the base as:

$n_{base}=0.425mol/L*0.1L=0.0425mol$

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$\frac{4.36g}{0.0425mol} =102.6g/mol$

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$102.6g/mol-16g/mol-1g/mol=85.6g/mol$

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

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3 years ago