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kati45 [8]
3 years ago
7

Hunter drew a representation of the atoms of a gas. The illustration shows atoms moving freely at high speeds.

Chemistry
1 answer:
insens350 [35]3 years ago
8 0

hunter did good wih the atoms of a gas

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What compounds break up into ions solution? ​
Korolek [52]

Answer:

Acids are compounds that dissociate (break) into hydrogen (H+) ions and another compound when placed in an aqueous solution.

Explanation:

5 0
3 years ago
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When 18.5 g of HgO(s) is decomposed to form Hg(l) and O2(g), 7.75 kJ of heat is absorbed at standard-state conditions. What is t
taurus [48]

Answer:

The standard enthalpy of formation of HgO is -90.7 kJ/mol.

Explanation:

The reaction between Hg and oxygen is as follows.

\text{Hg(l)}+\frac{1}{2}{O_{2}\rightarrow \text{HgO(s)}

From the given,

Molar mass of HgO = 216.59 g/mol

Mass of HgO decomposed = 18.5 g

Amount of heat absorbed = 7.75 kJ

From the reaction,

The standard  enthalpy of formation = +7.75\times\frac{kJ}{18.5 g}\frac{216.59}{1mol} \,\,= +90.7 kJ/mol

During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.

For the formation of 1 mol of HgO , 90.7 kJ of energy is release

Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol

5 0
3 years ago
What is the balanced equation if copper metal reacts with oxygen gas to form copper oxide
katrin [286]

Answer:

2Cu + O2 ----------------> 2CuO

5 0
3 years ago
Frank wants to make a simple electromagnet. Which of these does Frank need to have to create the electromagnet? A. iron filings
Helga [31]
C
He needs an battery to make the simple electromagnet
6 0
3 years ago
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A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
3 years ago
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