Answer:
464.373 ft / s, 43200 ft/s²
Explanation:
200 mi/h = 293.333 ft/s
3 mi/h² = 3 × (1 ft / s² / 2454.5454) = 0.0012222 = acceleration of the airplane
velocity of the rotating propeller Vr = ωr where ω is the angular rate = 120 rad/s and the radius = 6 ft /2 = 3 ft = 120 × 3 = 360 ft / s
Velocity of the particle = resultant of the velocities = √ ( 293.333² + 360² ) = 464.373 ft / s
centripetal acceleration = Vr² / r = 360² / 3 = 43200 ft/s²
acceleration of the particle = resultant accelerations = √ ( 0.001222² + 43200²) = 43200 ft/s²
Answer:
Larger
Explanation:
When a vehicle is accelerated, the weight of the vehicle and the driver is transferred to the front of the rear of the car.
This transferred weight is nothing but the additional weight that presses the car's suspension in the downward direction thereby affecting tire contact patch in the rear due to which the rear tires loses adhesion.
Well if you read closely, it says ELECTRICAL current. Therefore it must be A
Answer:
D
Explanation:
Copy all elements of b into a