Answer:
The original length of the specimen is found to be 76.093 mm.
Explanation:
From the conservation of mass principal, we know that the volume of the specimen must remain constant. Therefore, comparing the volumes of both initial and final state as state 1 and state 2:
Initial Volume = Final Volume
πd1²L1/4 = πd2²L2/4
d1²L1 = d2²L2
L1 = d2²L2/d1²
where,
d1 = initial diameter = 19.636 mm
d2 = final diameter = 19.661 mm
L1 = Initial Length = Original Length = ?
L2 = Final Length = 75.9 mm
Therefore, using values:
L1 = (19.661 mm)²(75.9 mm)/(19.636 mm)²
<u>L1 = 76.093 mm</u>
Answer:
The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.
Explanation:
Concentration of Ge (
) = 15%
Concentration of Si (C
) = 85%
Density of Germanium (ρ
) = 5.32 g/cm³
Density of Silicon (ρ
) = 2.33 g/cm³
Atomic mass of Ge (A
)= 72.64 g/mol
To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:
No of Ge atoms/cm³=[Avogadro's Number*
]/([
*A
/ρ
)+(C
*A
/ρ
)]
= (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]
= (9.03x10²²)/(2.048+26.499)
= (9.03x10²²)/(28.547)
No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³
C, being able to maintain legal information on grant programs
Answer:
See attached file please.
Explanation:
See attached file for detailed explanation and code.
import java.util.*;
class LinklistImplementQueue {
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
/* Creating object of class SLLQueue */
SLLQueue lq = new SLLQueue();
char ch;
do
{
System.out.println("\nQueue Operations");
System.out.println("1. ENQUEUE");
System.out.println("2. DEQUEUE");
int choice = scan.nextInt();
.
.
.
.
See attached file for complete code.