Answer:
As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.
Answer:

Explanation:
given data
Load P = 35 kN
Width of bar W = 50.8 mm
Breadth of bar B = 25 mm
Ratio of crack length to width α = a/W = 0.2
solution
we get here KI for a rectangular bar that is express as
................................1
here Y is the geometrical function
so
Y =
Y =
Y =
Y = 0.9878
so put here value in equation 1

= 5210.45 × 10³
= 5.21 MPa 
Short-term goals are planned for the near future while long-term goals will take longer to complete. An example of a short-term goal is trying to get into a certain college. A long-term goal is wanting to have a big family.
Answer:
When water is surrounding T_s = 34.17 degree C
When air surrounding T_S = 1434.7 degree C
from above calculation we can conclude that air is less effective than water as heat transfer agent
Explanation:
Given data:
length = 300 mm
Outer diameter = 30 mm
Dissipated energy = 2 kw = 2000 w
Heat transfer coefficient IN WATER = 5000 W/m^2 K
Heat transfer coefficient in air = 50 W/m^2 K
we know that 
From newton law of coding we have

is surface temp.
T - temperature at surrounding
![P = hA(T_s - T_{\infity})[tex]\frac{P}{\pi hDL} = (T_s - T_{\infity})](https://tex.z-dn.net/?f=P%20%3D%20hA%28T_s%20-%20%20T_%7B%5Cinfity%7D%29%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7BP%7D%7B%5Cpi%20hDL%7D%20%3D%20%20%28T_s%20-%20%20T_%7B%5Cinfity%7D%29)
solving for[/tex] T_s [/tex] w have



When air is surrounding we have



from above calculation we can conclude that air is less effective than water as heat transfer agent
Answer:
Explanation:
effective delay = delay when no traffic x 
effective delay = 