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Marina CMI [18]
3 years ago
6

A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

ic field = (0.1 T) .The induced electric current in the coil is 10 mA and its resistance is 10Ω. What is the speed of the wire?
Physics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance R= 10\Omega

We need to calculate the  speed of the wire

Using formula of emf

\epsilon=Bvl

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value of \epsilon into the formula of current

I=\dfrac{Bvl}{R}

v=\dfrac{IR}{Bl}

v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}

v= 5\ m/s

Hence, The speed of the wire is 5 m/s.

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A scaffold of mass 77 kg and length 5.0 m is supported in a horizontal position by a vertical cable at each end. A window washer
Lynna [10]

Answer:

A) T2 = 912.88 N

B) T1 = 607.12 N

Explanation:

First of all, we see that the sum of the tensions is equal to the total weight.

Now, for the scaffold, weight; W_s = 77 x 9.8 = 755.6 N

For the window washer, Weight; W_w = 78 x 9.8 = 764.4 N

Total weight;W_t = W_s + W_w

W_t = 755.6 N + 764.4 N = 1520 N

Thus,

T1 + T2 = 1520

Where T1 and T2 are the tensions in farther and nearer cables respectively.

Now, we need to do a torque problem.

The window washer is 1.8m from the right end of the scaffold and so the weight of the scaffold is at its center. This is 2.5 m from either end. Let the pivot point be at right end of the scaffold.

For the window washer, counter clockwise torque = 764.4 x 1.5 = 1146.6 N.m

For the scaffold, counter clockwise torque = 755.6 x 2.5 = 1889 N.m

Total Torque; T = 1146.6 + 1889 = 3035.6 N.m

For the cable at the left end of the cable, clockwise torque = T1 x 5

Set this equal to the total counter clockwise torque and solve for T1.

Thus,

T1 x 5 = 3035.6

T1 = 3035.6 ÷ 5 = 607.12 N

T2 = 1520 – 607.12 = 912.88 N

6 0
3 years ago
Consider three force vectors F~ 1 with magnitude 43 N and direction 38◦ , F~ 2 with magnitude 26 N and direction −140◦ , and F~
Rama09 [41]

Answer:

34.70 N

Explanation:

Given :

F~ 1 = 43 N in direction 38◦

F~ 2 = 26 N in direction −140◦

F~ 3 = 27 N in direction 110◦

Therefore,

F~x = 43 cos (38) + 26 cos (-140) + 27 cos (110)

      = 43  (0.7) + 26  (-0.7) + 27  (-0.3)

      =  3.8

F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)

      = 43  (0.6) + 26  (-0.6) + 27  (0.9)

      = 34.5

so, F~ = $ \sqrt{3.8^2 + 34.5^2}$

          = 34.70 N

6 0
3 years ago
A car speeds up from 10 m/s to 24 m/s. Change in velocity
JulsSmile [24]

Answer:

14m/s

Explanation:

subtract initial velocity by final velocity

5 0
2 years ago
ring a race a swimmer completes two laps. The first lap is From point A to B; the second is from B to A. Each lap is 60 meters l
cupoosta [38]

Answer:

Total time to complete the race = 45 sec

Explanation:

We have given that each lap is 60 m long

Average speed for the first lap = 2 m/sec

So time taken to complete the first lap time\ t=\frac{distance}{speed}=\frac{60}{2}=30sec

Average speed for second lap = 2 m/sec

So time taken to cover the second lap time\ t=\frac{distance}{speed}=\frac{60}{4}=15sec

So total time to complete the race = 30 +15 =45 sec

4 0
3 years ago
How do we solve problems that involve universal gravitation?
kherson [118]

Answer:

find the masses of one is three times the mass of the other.

4 0
3 years ago
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