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Marina CMI [18]
3 years ago
6

A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

ic field = (0.1 T) .The induced electric current in the coil is 10 mA and its resistance is 10Ω. What is the speed of the wire?
Physics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance R= 10\Omega

We need to calculate the  speed of the wire

Using formula of emf

\epsilon=Bvl

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value of \epsilon into the formula of current

I=\dfrac{Bvl}{R}

v=\dfrac{IR}{Bl}

v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}

v= 5\ m/s

Hence, The speed of the wire is 5 m/s.

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Answer:

I guess that we want to find how much money you get each week.

We know that the job pays $8.60 per hour.

We know that you work 20 hours per week.

Then the gross pay (the total money that you earn) in a week is 20 times $8.60, or:

20*$8.60 = $172.

Now we know that your employer witholds:

10% + 7.65% + 5% = 22.65%

Then your employer withholds 22.65% of your gross pay.

if the 100% of your gross pay is $172

Then the 22.65% will be:

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A rotating space station is said to create "artificial gravity" - a loosely-defined term used for an acceleration that would be
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Explanation:

The artificial gravity generated by the rotating space station is the same centripetal acceleration due to the rotational motion of the station, which is given by:

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Here, r is the radius and v is the tangential speed, which is given by:

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Here \omega is the angular velocity, we replace (2) in (1):

a_c=\frac{(\omega r)^2}{r}\\\\a_c=\omega^2r

Recall that r=\frac{d}{2}=\frac{200m}{2}=100m.

Solving for \omega:

\omega=\sqrt{\frac{a_c}{r}}\\\omega=\sqrt{\frac{9.8\frac{m}{s^2}}{100m}}\\\omega=0.31\frac{rad}{s}

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