Ask question

Ask question

All categories

Marina CMI [18]

3 years ago

6

A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

ic field = (0.1 T) .The induced electric current in the coil is 10 mA and its resistance is 10Ω. What is the speed of the wire?

1 answer:

Amanda [17]3 years ago

6 0

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance $R= 10\Omega$

We need to calculate the speed of the wire

Using formula of emf

$\epsilon=Bvl$

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value of $\epsilon$ into the formula of current

$I=\dfrac{Bvl}{R}$

$v=\dfrac{IR}{Bl}$

$v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}$

$v= 5\ m/s$

Hence, The speed of the wire is 5 m/s.

You might be interested in

Is the ratio between the sine of an angle of incidence to the sine of an angle of refraction is called the refractive index?

motikmotik

Answer:

Yes

Explanation:

Yes it is called the refractive index denoted by n

n=sin<i/sin<r

6 0

3 years ago

Read 2 more answers

A person paddles down river at an average speed of 4km

adoni [48]

Nice paddling. Thanks for sharing.
Do you have some question to ask ?

7 0

3 years ago

Read 2 more answers

Why is current a scalar quantity?

Nutka1998 [239]

Despite current has a magnitude and a direction, like vectors, it is a scalar because it doesn't obey laws of vector addition. For instance, if we consider a junction of $90^{\circ}$ in a circuit, and two currents entering this junction, we know that the resultant current is just the algebraic sum of the two currents, not the vector sum, so it is not a vector quantity.

5 0

3 years ago

You have a two-wheel trailer that you pull behind your ATV. Two children with a combined mass of 76.2 kg hop on board for a ride

marin [14]

a) The spring constant is 12,103 N/m

b) The mass of the trailer 2,678 kg

c) The frequency of oscillation is 0.478 Hz

d) The time taken for 10 oscillations is 20.9 s

Explanation:

a)

When the two children jumps on board of the trailer, the two springs compresses by a certain amount

$\Delta x = 6.17 cm = 0.0617 m$

Since the system is then in equilibrium, the restoring force of the two-spring system must be equal to the weight of the children, so we can write:

$2mg = k'\Delta x$ (1)

where

m = 76.2 kg is the mass of each children

$g=9.8 m/s^2$ is the acceleration of gravity

$k'$ is the equivalent spring constant of the 2-spring system

For two springs in parallel each with constant k,

$k'=k+k=2k$

Substituting into (1) and solving for k, we find:

$2mg=2k\Delta x\\k=\frac{mg}{\Delta x}=\frac{(76.2)(9.8)}{0.0617}=12,103 N/m$

b)

The period of the oscillating system is given by

$T=2\pi \sqrt{\frac{m}{k'}}$

where

And for the system in the problem, we know that

T = 2.09 s is the period of oscillation

m is the mass of the trailer

$k'=2k=2(12,103)=24,206 N/m$ is the equivalent spring constant of the system

Solving the equation for m, we find the mass of the trailer:

$m=(\frac{T}{2\pi})^2 k'=(\frac{2.09}{2\pi})^2 (24,206)=2,678 kg$

c)

The frequency of oscillation of a spring-mass system is equal to the reciprocal of the period, therefore:

$f=\frac{1}{T}$

where

f is the frequency

T is the period

In this problem, we have

T = 2.09 s is the period

Therefore, the frequency of oscillation is

$f=\frac{1}{2.09}=0.478 Hz$

d)

The period of the system is

T = 2.09 s

And this time is the time it takes for the trailer to complete one oscillation.

In this case, we want to find the time it takes for the trailer to complete 10 oscillations (bouncing up and down 10 times). Therefore, the time taken will be the period of oscillation multiplied by 10.

Therefore, the time needed for 10 oscillations is:

$t=10T=10(2.09)=20.9 s$

#LearnwithBrainly

7 0

3 years ago

Friction is generated when?

valkas [14]

Things are rubbed against each other

8 0

3 years ago