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Marina CMI [18]

3 years ago

6

A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet

ic field = (0.1 T) .The induced electric current in the coil is 10 mA and its resistance is 10Ω. What is the speed of the wire?

1 answer:

Amanda [17]3 years ago

6 0

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance $R= 10\Omega$

We need to calculate the speed of the wire

Using formula of emf

$\epsilon=Bvl$

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value of $\epsilon$ into the formula of current

$I=\dfrac{Bvl}{R}$

$v=\dfrac{IR}{Bl}$

$v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}$

$v= 5\ m/s$

Hence, The speed of the wire is 5 m/s.

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A potential difference of 15 V produces a current of 0.60 amps in a piece of copper wire. What is the resistance of the wire?

ale4655 [162]

Answer:

R = 25 Ohms

Explanation:

Given the following data;

Voltage (p.d) = 15 V

Current = 0.6 A

To find the resistance of the wire;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

$V = IR$

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

$R = \frac {V}{I}$

Substituting into the equation, we have;

$R = \frac {15}{0.6}$

R = 25 Ohms

8 0

3 years ago

9. What is the total kinetic energy (KEtran + KErot) of a solid cylinder with mass M = 2.50 kg and radius R = 0.5 m that rolls w

GarryVolchara [31]

Answer:

110.25 J

Explanation:

We are given that

Mass,M=2.5 kg

Radius,R=0.5 m

Distance,d=4.5 m

Initial speed,u=0

We have to find the total kinetic energy

According to law of conservation of energy

Total kinetic energy=Potential energy=mgh

Where g= $9.8m/s^2$

Using the formula

Total kinetic energy= $2.5\times 9.8\times 4.5$

Total kinetic energy $=110.25 J$

4 0

3 years ago

A tightly closed, well-insulated vacuum flask is an example of which type of<br> system?

nignag [31]

Answer:

Isolated

Explanation:

4 0

4 years ago

Calculate the first and second order angles for light of wavelength 400. nm and 700. nm of the grating contains 1.00 x 104 lines

Verdich [7]

Answer:

$23.58^{\circ}$ and $53.13^{\circ}$

$44.43^{\circ}$ , second order does not exist

Explanation:

n = Number of lines grating = $1\times10^4\ \text{Lines/cm}$

$\lambda$ = Wavelength

m = Order

Distance between slits is given by

$d=\dfrac{1}{n}\\\Rightarrow d=\dfrac{1}{1\times 10^4}\\\Rightarrow d=10^{-6}\ \text{m}$

$\lambda=400\ \text{nm}$

m = 1

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\\\Rightarrow \theta=\sin^{-1}\dfrac{1\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=23.58^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=53.13^{\circ}$

The first and second order angles for light of wavelength 400 nm are $23.58^{\circ}$ and $53.13^{\circ}$ .

$\lambda=700\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 700\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=44.43^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 700\times 10^{-9}}{10^{-6}}$

Here $\dfrac{2\times 700\times 10^{-9}}{10^{-6}}=1.4>1$ so there is no second order angle for this case.

The first order angle for light of wavelength 700 nm are $44.43^{\circ}$ .

Second order angle does not exist.

5 0

3 years ago

Please help me rn rn

vfiekz [6]

Answer:

merry Christmas ⛄

7 0

2 years ago