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3 years ago

Balance the equation in the box. Click in the answer box to activate the palette. N2(g) + H2(g) → NH3(g)

Chemistry

1 answer:

lesantik [10]3 years ago

7 0

Answer:

N2(g) + 3H2(g) → 2 NH3(g)

Explanation:

N2(g) + H2(g) → NH3(g)

We start equaling the number of N atoms in both sides multiplying by 2 the NH3.

N2(g) + H2(g) → 2 NH3(g)

So we equals the H atoms (there are six in products sites)

N2(g) + 3 H2(g) → 2 NH3(g)

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This infectious disease requires a special mask for protection

11111nata11111 [884]

Answer:

the black plague

Explanation:

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3 years ago

Read 2 more answers

The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut

aivan3 [116]

Answer:

$Molarity=1.22\ M$

Explanation:

Given:

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (19 + 273.15) K = 292.15 K

Volume = 0.200 L

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K

⇒n = 0.008174 moles

From the reaction shown below:-

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

1 mole of $H_2SO_4$ react with 2 moles of $NaOH$

0.008174 mole of $H_2SO_4$ react with 2*0.008174 moles of $NaOH$

Moles of $NaOH$ = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.016348}{0.0134}\ M$

$Molarity=1.22\ M$

8 0

3 years ago

Calculate the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL.

Finger [1]

Considering the definition of dilution, the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL is 0.93 mL.

<h3>What is diluion</h3>

First of all, you have to know that when it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Molarity of the solution in this case</h3>

In this case, you know:

Ci= 4 M
Vi= 7 mL
Cf= ?
Vf= 30 mL

Replacing in the definition of dilution:

4 M× 7 mL= Cf× 30 mL

Solving:

(4 M× 7 mL)÷ 30 mL= Cf

In summary, the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL is 0.93 mL.

Learn more about dilution:

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brainly.com/question/22762236

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2 years ago

You are carrying out an experiment in the lab to study the glycolysis pathway. To do this, a liver extract (which is capable of

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Answer:

When C1 is labeled in glucose, it ends up in the methyl group of pyruvate.

Aldolase cleaves a hexose into two trioses.

[See the image attached].

Asterisk indicates the label.

When C1 is labeled in glucose, it ends up in the carboxyl group of pyruvate.

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3 years ago

Name the following ether: OCH2CH3

Lelu [443]

The name of the given ether is ethyl benzyl ether .

<h3>What are ethers?</h3>

Ethers are organic compounds formed when nan oxygen atom is bonded to two alkyl or aryl groups.

Ethers usually have relatively high boiling points as a result of the central oxygen atom. An example of an ether, is ethyl propyl ether

The name of the given ether is ethyl benzyl ether as it has a benzyl and ethyl group attached to the oxygen atom.

In conclusion, ethers are characterized by an oxygen atom bonded to two alkyl or aryl groups.

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2 years ago