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3 years ago

A cart is rolling down a ramp. if the angle of the ramp is increased to make the ramp steeper the cart will

Physics

1 answer:

Westkost [7]3 years ago

8 0

The speed of the carts descent will increase? Not quite sure what you’re asking.

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Does the speedometer of a car measure speed or velocity? Explain.

deff fn [24]

Car speedometer only measures speed and doesn't give any information about direction. So yes to speed, no to velocity. ... Therefore the object CANNOT have a varying speed if its velocity is constant.

6 0

3 years ago

A jet engine gets its thrust by taking in air, heating and compressing it, and

nadya68 [22]

Answer:

$F=ma=20\ Kg\ 400\ m/s^2=8,000\ Nw$

Explanation:

Thrust is known as a reaction force which appears when a system expels or accelerates mass in one specific direction. If we know the acceleration and the mass of the air expelled by the jet engine, we can compute the thrust .

The acceleration is calculated by using the dynamics formula

$\displaystyle a=\frac{v_f-v_o}{t}$

The values are

$v_f=500\ m/s,\ v_o=100\ m/s,\ t=1\ sec$

$\displaystyle a=\frac{500-100}{1}=400\ m/s^2$

The thrust is

$F=ma=20\ Kg\ 400\ m/s^2=8,000\ Nw$

4 0

3 years ago

· A hot, just-minted copper coin is placed in 101 g of water to cool. The water

Mariana [72]

Answer:

135g

Explanation:

6 0

3 years ago

The Assignment: A fixed quantity of an ideal gas (R 0.28 kJ/kgK; Cv-0.71kJ/kgK) is expanded from an initial condition of 35 bar,

Nikolay [14]

Answer:

Index of expansion: 4.93

Δu = -340.8 kJ/kg

q = 232.2 kJ/kg

Explanation:

The index of expansion is the relationship of pressures:

pi/pf

The ideal gas equation:

p1*v1/T1 = p2*v2/T2

p2 = p1*v1*T2/(T2*v2)

500 C = 773 K

20 C = 293 K

p2 = 35*0.1*773/(293*1.3) = 7.1 bar

The index of expansion then is 35/7.1 = 4.93

The variation of specific internal energy is:

Δu = Cv * Δt

Δu = 0.71 * (20 - 500) = -340.8 kJ/kg

The first law of thermodynamics

q = l + Δu

The work will be the expansion work

l = p2*v2 - p1*v1

35 bar = 3500000 Pa

7.1 bar = 710000 Pa

q = p2*v2 - p1*v1 + Δu

q = 710000*1.3 - 3500000*0.1 - 340800 = 232200 J/kg = 232.2 kJ/kg

7 0

3 years ago

Joe the house painter stands on a uniform oak board weighing 600 N and held up by vertical ropes at each end. Joe has been dieti

Mamont248 [21]

Answer

given,

weight of the oak board = 600 N

Weight of Joe = 844 N

length of board = 4 m

Joe is standing at 1 m from left side

vertical wire is supporting at the end.

Assuming the system is in equilibrium

T₁ and T₂ be the tension at the ends of the wire

equating all the vertical force

T₁ + T₂ = 600 + 844

T₁ + T₂ = 1444...........(1)

taking moment about T₂

T₁ x 4 - 844 x 3 - 600 x 2 = 0

T₁ x 4 = 3732

T₁ = 933 N

from equation (1)

T₂ = 1444 - 933

T₂ = 511 N

3 0

4 years ago

A cart is rolling down a ramp. if the angle of the ramp is increased to make the ramp steeper the cart will​

A cart is rolling down a ramp. if the angle of the ramp is increased to make the ramp steeper the cart will