The magnitude of the charge on the balloon is 1.6 x 10⁻¹² C.
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What is the magnitude of the charge on the ball?</h3>
The magnitude of the charge on the ball is calculated by determining the total charge equivalent to the given number of electrons.
The charge of one electron = 1.6 x 10⁻¹⁹ Coulombs
Now, we are going to estimated the total charge of 1 x 10⁷ electrons.
1 electron = 1.6 x 10⁻¹⁹ C
1 x 10⁷ electrons = ?
= (1 x 10⁷ electrons x 1.6 x 10⁻¹⁹ C) / (1 electron)
= 1.6 x 10⁻¹² C
Thus, the total charge of 1 x 10⁷ electrons is obtained by multiplying the magnitude of charge of one electron to the entire given electrons.
Learn more about charge of electron here: brainly.com/question/9317875
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Because water is more dense than the object but rubbing alcohol is less dense than the object
Answer:When the length of a string is changed, it will vibrate with a different frequency.Shorter strings have higher frequency and therefore higher pitch.
Answer:
The. Machine must detect a shift of
1 Hz
Explanation:
Frequency shift is given as
={ ( Vsound +V/ V sound -V) -1}f emitted
So by substitution we have
= { 1540+4E-4/1540-4E)-1) 2*10^6
= 1Hz
Answer:
Very easy question
For x-component, we use Fₓ = Fcosα
For y-component, we use Fy = Fsinα
The major problem is with angle α.
Here α = 90+30
Because the angle is measured from +ve X-axis.
By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.
So for further calculation,
Fₓ = Fcos(90+30) = 25(-sin30)
Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"
As it is
Fy = Fsin(90+30) = Fcos30
Fy = 25 (√3 /2) = 25√3/2
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