Answer:
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<u><em>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment
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Answer:
P ( 2.5 < X < 7.5 ) = 0.7251
Explanation:
Given:
- The pmf for normal distribution for random variable x is given:
f(x)=0.178 exp(-0.100(x-4.51)^2)
Find:
the fraction of individuals demonstrating a response in the range of 2.5 to 7.5.
Solution:
- The random variable X follows a normal distribution with mean u = 4.51, and standard deviation s.d as follows:
s.d = sqrt ( 1 / 0.1*2)
s.d = sqrt(5) =2.236067
- Hence, the normal distribution is as follows:
X ~ N(4.51 , 2.236)
- Compute the Z-score values of the end points 2.5 and 7.5:
P ( (2.5 - 4.51) / 2.236 < Z < (7.5 - 4.51 ) / 2.236 )
P ( -0.898899327 < Z < 1.337168651 )
- Use the Z-Table for the probability required:
P ( 2.5 < X < 7.5 ) = P ( -0.898899327 < Z < 1.337168651 ) = 0.7251
Sound requires a medium to travel. Sound cannot travel in vacuum in space while light can. Therefore, the receiver from earth receives only light sent from moon, not sound.
Explanation:
- Sound is created by vibrations that requires medium to travel. The medium can be solid, liquid, or gas. Whatever it is, a medium is required.
- In space, there is no solid, liquid, or gas. In other words, it is vacuum. Sound waves cannot travel through vacuum.
- Light waves, on the other hand, can travel through vacuum. Hence, if the transmitter on moon emits sound waves and light waves, receiver from earth picks only the light waves.
Answer:
Technician A
Explanation: Technician A is correct. Technician B is wrong, as an oil leak can trickle down onto other engine components, away from where the leak actually is.
To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.
The gas ideal law is given as,
Where,
P = Pressure
V = Volume
m = mass
R = Gas Constant
T = Temperature
Our data are given by
Note that the pressure to 38°C is 0.06626 bar
PART A) Using the ideal gas equation to calculate the mass flow,
Therfore the mass flow rate at which water condenses, then
Re-arrange to find
PART B) Enthalpy is given by definition as,
Where,
= Enthalpy of dry air
= Enthalpy of water vapor
Replacing with our values we have that
In the conversion system 1 ton is equal to 210kJ / min
The cooling requeriment in tons of cooling is 437.2.